slope = (25-4)/(30-10)
slope = 21/20
slope =21/20
using point slope form
y-y1 = m(x-x1)
y-4 = 21/20 (x-10)
y = 21/20x -21/2 +4
y = 21/20 x -21/2 +8/2
y = 21/20x -13/2
let x=40
y = 21/20 (40) -13/2
y = 42-13/2
y = 35.5 games
If we round the slope to 1
slope =1
using point slope form
y-y1 = m(x-x1)
y-4 = 1 (x-10)
y = 1x -10 +4
y = x -6
let x=40
y = 40-6
y = 34 games
Answer:
Top right.
Step-by-step explanation:
So we want a line with a slope of 3 and passes through (2,5).
To do so, we can use the point-slope form.
The point-slope form is:
m is the slope and x₁ and y₁ is an ordered pair.
Thus, let m be 3, y₁ be 5, and x₁ be 2. Thus:
Our answer is the top right :)
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
16
Step-by-step explanation:
To find the radius find the distance between (4,0) and (4,8). The radius is 8. Then multiply by 2 to find out the diameter.
