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Aleksandr-060686 [28]
3 years ago
14

Pls help i dont know what to do

Mathematics
2 answers:
ad-work [718]3 years ago
7 0

Answer:

-26

Tip for solving related problems: use order of operations

8090 [49]3 years ago
6 0

Answer:

-26

Step-by-step explanation:

-5 x 7=-35

-35 + 9=-26

5/5=1

-26 x 1=-26

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8) A school community had planned to reduce the number of grade 9 students per class room by constructing additional class rooms
Allisa [31]

Step-by-step explanation:

Let "c" be the original number of classrooms.

The 1200/c was the original number of students per classroom.

----

Equation:

1200/(c-4) = (1200/c)+10

Multiply thru by c(c-4)

---

1200c = 1200(c-4)+10c(c-4)

---

1200c = 1200c-4800 + 10c^2-40c

----

10c^2-40c-4800 = 0

c^2-4c-480 = 0

Factor:

(c-24)(c+20) = 0

---

Positive solution:

c = 24 (# of classrooms originaly planned)

7 0
2 years ago
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Step-by-step explanation:

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3 years ago
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N76 [4]

Answer:

At-most 3 birdhouses.

Step-by-step explanation:

Let B represent the number of birds and H represent the number of birdhouses that Nathaniel can build with his Lego blocks.

We have been given that Nathaniel builds birds and birdhouses using Lego blocks. The inequality 43B+215H\leq3000 represents the number of birds and birdhouses Nathaniel could build.

To find the number of birdhouses that Nathaniel can build after making 50 birds, we will substitute B=50 in our given inequality and then solve for H.

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Let us subtract 2150 from both sides of our inequality.

2150-2150+215H\leq3000-2150

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Let us divide both both sides of our inequality by 215.

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H\leq3.953488

As Nathaniel can make build less than or equal to 3.953488 and the biggest integer less than or equal to 3.953 is 3, therefore, Nathaniel can build at-most 3 birdhouses with remaining Lego blocks.

3 0
2 years ago
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Answer:

First statement is correct

Step-by-step explanation:

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6 0
3 years ago
Edward can run 1/2 mile in 300 seconds. What is his unit of rate
sattari [20]
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3 years ago
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