Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.
<h3>Probability</h3>
Using Binomial Distribution
Given:
n = 3
p = 0.75
q = 1-0.95 = 0.25
Hence:
P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³
P[≥2] = P[2] + P[3]=0.421875+0.421875
P[≥2] = P[2] + P[3]=0.84375×100
P[≥2] = P[2] + P[3]=84% (Approximately)
Inconclusion the probability that at least two plan on attending college is 84%.
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Answer:
The missing area for both sides is 48ft²
the missing dimension is 12ft
Step-by-step explanation:
Add all the areas up
12+36+12+36=96
192-96=96
96÷2=48
48÷4=12
Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or

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Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality
is the same as 
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Let's multiply both sides by 15 to clear out the fractions

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Now isolate the variable b

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
Answer:
Yes, and?
Step-by-step explanation:
Answer:
Dasha has 52 roses
Step-by-step explanation:
Rewrite the first sentence in an equation: (D= Dasha) (A= Anna)
D=4A
Rewrite the second sentence in an equation:
A+39=D
1) Substitute A+39 as D in the first equation:
A+39=4A
2) Subtract A from both sides:
3A=39
3) Divide both sides by 3:
A=13
4) Now substitute 13 as A in the second equation:
13+39=D
5) Solve:
D=52