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Marrrta [24]
3 years ago
8

Where is tge vertex of the graph of y=-x^2

Mathematics
1 answer:
likoan [24]3 years ago
4 0
\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
y=-x^2\implies y=-1(x-\stackrel{h}{0})^2+\stackrel{k}{0}
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A survey of high school juniors found the 75% of the students plan on attending college. If you pick 3 students at random, what
olya-2409 [2.1K]

Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.

<h3>Probability</h3>

Using Binomial Distribution

Given:

n = 3

p = 0.75

q = 1-0.95 = 0.25

Hence:

P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³

P[≥2] = P[2] + P[3]=0.421875+0.421875

P[≥2] = P[2] + P[3]=0.84375×100

P[≥2] = P[2] + P[3]=84% (Approximately)

Inconclusion the probability that at least two plan on attending college is 84%.

Learn more about probability here:brainly.com/question/24756209

4 0
2 years ago
Need help Will give you the brainliest
marshall27 [118]

Answer:

The missing area for both sides is 48ft²

the missing dimension is 12ft

Step-by-step explanation:

Add all the areas up

12+36+12+36=96

192-96=96

96÷2=48

48÷4=12

5 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
A is used when the owner is still alive.
olga nikolaevna [1]

Answer:

Yes, and?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me with this problem
Naya [18.7K]

Answer:

Dasha has 52 roses

Step-by-step explanation:

Rewrite the first sentence in an equation: (D= Dasha) (A= Anna)

D=4A

Rewrite the second sentence in an equation:

A+39=D

1) Substitute A+39 as D in the first equation:

A+39=4A

2) Subtract A from both sides:

3A=39

3) Divide both sides by 3:

A=13

4) Now substitute 13 as A in the second equation:

13+39=D

5) Solve:

D=52

4 0
3 years ago
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