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Marrrta [24]
3 years ago
8

Where is tge vertex of the graph of y=-x^2

Mathematics
1 answer:
likoan [24]3 years ago
4 0
\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
y=-x^2\implies y=-1(x-\stackrel{h}{0})^2+\stackrel{k}{0}
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