So, you have to have your equation in terms of dimes. What you said about what he has: four more nickels than dimes in his pocket. Will help with our equation. We know what a nickel and dime is worth. A nickel is .05 and a dime is .1 We don't know how many dimes are in his pocket, since we're trying to solve it. .1x+(4+x).05=1.25; In the parenthesis, it shows how there are four more nickels. Let's solve it now. .1x + (4+x).05=1.25 .1x + .2+ .05x = 1.25; Let's add like terms. .15x + .2 = 1.25; Subtract .2 from both sides. .15x= 1.05 1.05÷.15= 7 =x There are 7 dimes in his pocket, let's check our answer. We now know there are 11 nickels, since there are four more nickels than dimes. 11(.05) +.1(7) = 1.25 .55+ .7 = 1.25 Now that we've tried it, we know there are 7 dimes in his pocket. Tell me if this helps!
