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just olya [345]
3 years ago
7

What is the solution to the equation 3sqrt(5x-4)=3sqrt(7x+8)

Mathematics
2 answers:
Nady [450]3 years ago
5 0

Answer:

<em>The answer is:   'no solution'</em>

Step-by-step explanation:

The given equation is:   3\sqrt{5x-4}=3\sqrt{7x+8}

Dividing both sides of the equation by 3, we will get.....

\sqrt{5x-4}=\sqrt{7x+8}

Taking square on both sides.....

(\sqrt{5x-4})^2=(\sqrt{7x+8})^2\\ \\ 5x-4=7x+8\\ \\ 5x-7x=8+4\\ \\ -2x=12\\ \\ x=\frac{12}{-2}=-6

Plugging this x=-6 back to the given equation......

3\sqrt{5(-6)-4}=3\sqrt{7(-6)+8}\\ \\ 3\sqrt{-34}=3\sqrt{-34}

<em>As we are getting a negative number inside the square root, so the equation becomes imaginary. Thus x=-6 is a restricted value.</em>

Hence, there is 'no solution' for this equation.

m_a_m_a [10]3 years ago
4 0
X = -6

However this is an extraneous solution since it would make the number under the sqrt a negative number. 
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