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3 years ago

What is the solution to the equation 3sqrt(5x-4)=3sqrt(7x+8)

Mathematics

2 answers:

Nady [450]3 years ago

5 0

Answer:

The answer is: 'no solution'

Step-by-step explanation:

The given equation is: $3\sqrt{5x-4}=3\sqrt{7x+8}$

Dividing both sides of the equation by 3, we will get.....

$\sqrt{5x-4}=\sqrt{7x+8}$

Taking square on both sides.....

$(\sqrt{5x-4})^2=(\sqrt{7x+8})^2\\ \\ 5x-4=7x+8\\ \\ 5x-7x=8+4\\ \\ -2x=12\\ \\ x=\frac{12}{-2}=-6$

Plugging this $x=-6$ back to the given equation......

$3\sqrt{5(-6)-4}=3\sqrt{7(-6)+8}\\ \\ 3\sqrt{-34}=3\sqrt{-34}$

As we are getting a negative number inside the square root, so the equation becomes imaginary. Thus $x=-6$ is a restricted value.

Hence, there is 'no solution' for this equation.

m_a_m_a [10]3 years ago

4 0

X = -6

However this is an extraneous solution since it would make the number under the sqrt a negative number.

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Type the correct answer in each box.

Vitek1552 [10]

Answer:

The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( -4,2).

The coordinates of the point that is a reflection of Y across the y-axis are ( 4,-2).

Step-by-step explanation:

Reflection across x-axis

The rule used for Reflection across x-axis is that y-coordinate becomes negated while x coordinate remains same.

So,

The coordinates of the point that is a reflection of Y(-4, -2) across the x-axis are ( -4,2).

Because according to definition, x-coordinate remains same, while y-coordinate is negated. So x-coordinate = -4, y-coordinate = 2

Reflection across y-axis

The rule used for Reflection across y-axis is that x-coordinate becomes negated while y coordinate remains same.

So,

The coordinates of the point that is a reflection of Y across the y-axis are ( 4,-2).

Because according to definition, y-coordinate remains same, while x-coordinate is negated. So x-coordinate = 4, y-coordinate = -2

7 0

3 years ago

What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?

iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

triangles

- The slant height of it = $\sqrt{(\frac{1}{2}b)^{2}+h^{2}}$ , where

b is the length of its base and h is the perpendicular height

- Its lateral area = $\frac{1}{2}.p.l$ , p is the perimeter of the base

and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = $\sqrt{(\frac{1}{2}b)^{2}+h^{2}}$

∴ l = The slant height of it = $\sqrt{(\frac{1}{2}.24)^{2}+5^{2}}$

∴ l = $\sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13$

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = $\frac{1}{2}.p.l$

∴ The lateral area = $\frac{1}{2}.(96).(13)$

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

4 0

3 years ago

Which intergers in each pair is greater? a.+12 or -21 b.+17 or -20

Annette [7]

Answer:

b is the answer by solomon

4 0

3 years ago

Can someone help with this

Zinaida [17]

Answer:

C and E

Step-by-step explanation:

-2/3 = -0.66

so hence forth

2/3 = 0.66

- (2/3) = -0.66 and

2/-3 = -0.66

5 0

3 years ago

The floor of a 15’ x 20’ rectangular room is being covered with carpet tiles each carpet tiles cover 6 ft.² of floor which of th

Blababa [14]

Answer:

15 * 20 / 6

Step-by-step explanation:

1. Find the area of the room, 300.

2. Just divide 300 from 6

3. you get 50 tiles

4. It's asking for an expression, so 15 * 20 / 6

6 0

3 years ago

Read 2 more answers