The median of this box and whisker plot is 73
A box and whisker plot is defined as a graphical method of displaying variation in a set of data. In most cases, a histogram analysis provides a sufficient display, but a box and whisker plot can provide additional detail while allowing multiple sets of data to be displayed in the same graph. Box and whisker plots are very effective and easy to read, as they can summarize data from multiple sources and display the results in a single graph. Box and whisker plots allow for comparison of data from different categories for easier, more effective decision-making.
From the given data, following can be inferred
- Population size: 18
- Median: 73
- Minimum: 55
- Maximum: 89
- First quartile: 61.75
- Third quartile: 83.5
- Interquartile Range: 21.75
which is demonstrated in the box and whisker plot below
Learn more about box and whisker plot here :
brainly.com/question/23091366
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Answer:
Step-by-step explanation:
If you go with Blackburn, you have to pay 25 bucks right off, for the web services hosting setup, that's for them to add your account, and allocate resources on their end for you.
After that, for every passing month, you have to pay 5.69 bucks for the service they provide on daily basis.
if you with Randall, they also charge for setup fee, just cheaper, $6 at once, and then for every month is $9.49.
Blackburn for
1 month 5.69(1) + 25
2 months 5.69(2) + 25
3 months 5.69(3) + 25
x months 5.69(x) + 25, or 5.69x + 25
Randall for
1 month 9.49(1) + 6
2 months 9.49(2) + 6
3 months 9.49(3) + 6
x months 9.49(x) + 6, or 9.49x + 6
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y = 5.69x + 25
y = 9.49x + 6
Given that mean=3750 hours and standard deviation is 300:
Then:
<span>a. The probability that a lamp will last for more than 4,000 hours?
P(x>4000)=1-P(x<4000)
but
P(x<4000)=P(z<Z)
where:
z=(x-</span>μ)/σ
z=(4000-3750)/300
z=0.833333
thus
P(x<4000)=P(z<0.8333)=0.7967
thus
P(x>4000)=1-0.7967=0.2033
<span>b.What is the probability that a lamp will last less than 3,000 hours?
P(x<3000)=P(z<Z)
Z=(3000-3750)/300
z=-2.5
thus
P(x<3000)=P(z<-2.5)=0.0062
c. </span><span>.What lifetime should the manufacturer advertise for these lamps in order that only 4% of the lamps will burn out before the advertised lifetime?
the life time will be found as follows:
let the value be x
the value of z corresponding to 0.04 is z=-2.65
thus
using the formula for z-score:
-2.65=(x-3750)/300
solving for x we get:
-750=x-3750
x=-750+3750
x=3000</span>
