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NemiM [27]
2 years ago
14

1.consider the function

Mathematics
1 answer:
marin [14]2 years ago
4 0

Function transformation involves changing the form of a function

  • The transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4
  • The x and y intercepts are -0.67 and 1.91, respectively.
  • The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

The functions are given as:

\mathbf{f(x) = log3x}

\mathbf{g(x) = 4log3(x+1)}

<u>(a) The transformation from f(x) to g(x)</u>

First, f(x) is shifted left by 1 unit.

The rule of this transformation is:

\mathbf{(x,y) \to (x + 1,y)}

So, we have:

\mathbf{f'(x) = log3(x + 1)}

Next. f'(x) is vertically stretched by a factor of 4.

The rule of this transformation is:

\mathbf{(x,y) \to (x,4y)}

So, we have:

\mathbf{g(x) = 4log3(x+1)}

Hence, the transformation from f(x) to g(x) is a horizontal shift 3 units left, followed by a vertical stretch by a factor of 4

<u>(b) Sketch of g(x)</u>

See attachment

<u>(c) Asymptotes</u>

The graphs of g(x) have no asymptote

<u>(d) The intercepts, and the behavior of f(x)</u>

The graph crosses the x-axis at x =-0.67, and it crosses the y-axis at y = 1.91

Hence, the x and y intercepts are -0.67 and 1.91, respectively.

The behavior of g(x) is that, g(x) approaches infinity, as x approaches infinity.

We know this because, the value of the function increases as x increases

Read more about function transformations at:

brainly.com/question/13810353

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(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
3 years ago
An angle less than 90 degrees ​
OverLord2011 [107]

Answer:

<u>Acute Angle</u>

Step-by-step explanation:

<u>Obtuse Angle</u> is greater than 90 degrees

<u>Right Angle</u> is exactly 90 degrees

<u>Acute Angle</u> is less than 90 degrees

5 0
3 years ago
A brownie recipe calls for 1 cup of sugar and 12 cup of flour to make one batch of brownies. To make multiple batches, the equat
PolarNik [594]

what is the question?

5 0
3 years ago
Read 2 more answers
in 4 minutes Liaa can type 140 words. If she has an essay taht is 700 words long , about how long will it take Liana to type it
Zanzabum

Answer: Lol your in collage I don't believe it anyway the answer is 20 min on the dot  

6 0
3 years ago
Which is the correct form of q(x) + r(x)/b(x) for expression 7x^4+x+14/x+2
BARSIC [14]
<span>(7x^4+x+14)/(x+2)
</span>(7x^4+x+14)----------------------|(x+2)
-14x³+x+14-------------------------7x³-14x²+28x-55------> q(x)
28x²+x+14
-55x+14
110+14=124------------------------> r(x)
<span>
 </span>r(x)=124
b(x)=x+2
q(x)=7x³-14x²+28x-55

then
q(x) + r(x)/b(x)---------> (7x³-14x²+28x-55)+(124)/(x+2)

the answer is (7x³-14x²+28x-55)+(124)/(x+2)
4 0
3 years ago
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