(1/2)[logb(b^2)+logb(8x)]
=(1/2)[2+logb(8x)]
=1+(1/2)logb(8x)
hope this helps you
Answer:
All Real Answers
Step-by-step explanation:
Step 1:
4 - 6x - 2 = - 6x + 2 Equation
Step 2:
2 - 6x = - 6x + 2 Subtract
Step 3:
2 = 2 Add 6x on both sides
Answer:
All Real Answers
Hope This Helps :)
First, you square numbers and multiply the exponents.
32^2 is 1024 and 6x2=12
4^2 is 16 and 4x2=8
The equation is now 1024m^12/16n^8
You divide the numbers and get 64
Since the m and n aren’t the same letter, you leave them alone
The answer is 64m^12n^8
Answer:
All fractions contain integers and rational numbers
have a nice day
Y = 2/3x + 3 is the answer