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vfiekz [6]
3 years ago
11

Melissa runs a dog-boarding service. The cost to board a dog for one day is $25.00. If the same dog owner wants to board their d

og for more than one day, the cost is $15.00 per additional day. Jared plans to use Melissa's dog-boarding service, and he budgets to spend no more than $150.00 to board his dog.
Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

Answer: 25 + 15x ≤ 150

Step-by-step explanation: For this problem we will write an inequality to represent this situation.

Let x equal each additional day.

25 + 15x ≤ 150

The inequality above states that the dog owner will spend $25 for the first day and then for each additional day the dog owner will spend $15, but is budget is no more than $150 that the dog owner can spend.

Kobotan [32]3 years ago
7 0

Answer:

8 days

Step-by-step explanation:

Cost = 25 + 15n

25 + 15n《150

15n《125

n《8.3333333333

At max, 8 days

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If paige lives 3 miles, and deigo lives 8 miles away, then you add 3 and 8 to get 11 milles
4 0
3 years ago
Yall please help meee
Lady_Fox [76]

Answer:

<u>12n + 2</u>

Step-by-step explanation:

w(n) = un + 2

w(3n) = 4(3n) + 2

ans = 12n + 2

hope it helps you

have a great day!!

6 0
2 years ago
Helppp!!!! please!!!
KatRina [158]

Answer:

Option B is the correct answer

Step-by-step explanation:

Center of the circle lie on point (-1, - 3) = (h, k)

\implies \: h =  - 1 \:  \: k =  - 3 \\radius \: r \:  = 2  \\ equation \: of \: circle \: in \: standard \: form \:  \\ is \: given \: as :  \\  {(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}  \\  {(x  +  1)}^{2}  +  {(y  +  3)}^{2}  =  {2}^{2}  \\  \purple{ \boxed{ \bold{ {(x  +  1)}^{2}  +  {(y  + 3)}^{2}  = 4}}}

8 0
2 years ago
If ST=19 and S lies at -4 , where could T be located?
Natasha2012 [34]

Answer:

15 or -23

Step-by-step explanation:

I think you probably already turned this in but in case you haven't:

ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?

So there's two directions we could go.

Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)

But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)

Please mark as Brainliest! :)

8 0
3 years ago
When the sun is at 31 above the horizon, a tree casts a 42 ft. shadow. how tall is the tree?
Fantom [35]
Answer: 25.2361459992ft

This question can be solved by a trigonometric equation. Shadow formed when something with height like a tree, so it can be pictured as a vertical line. Shadow is a length of and can be pictured as a horizontal line.  
In trigonometric, to find the vertical line length with horizontal line you need tan function. The sun angle will be used in the function, so the calculation would be: tan(31) x 42ft = 25.2361459992ft

5 0
3 years ago
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