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3 years ago

1.3.18

Mathematics

1 answer:

Galina-37 [17]3 years ago

4 0

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

$M = ( \frac{x1 + x2}{2} , \: \frac{y1 + y2}{2} )\\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-2, - 1) and ( - 4,10)

So we have

$M = ( \frac{ - 2 - 4}{2} \: , \: \frac{ - 1 + 10}{2} ) \\ = ( - \frac{ 6}{2} \: , \: \frac{9}{2} )$

We have the final answer as

$( - 3 \: , \frac{9}{2} )$

Hope this helps you

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A cylindrical water tank has a radius of 6 feet and a height of 20 feet. A larger tank with the same height has a volume that is

likoan [24]

Answer:

Radius of large cylinder $= 10.39 feet\\$

Step-by-step explanation:

Volume of the larger tank is three times the volume of smaller tank

Volume of smaller tank

$= \pi r^{2} h\\= (3.14) * 6^{2} * 20\\= 2260.8 ft^{3} \\$

Volume of larger tank

$= 3 * 2260.8 ft^3\\= 6782.4 ft^3\\$

Or it can also be written as

$\pi r^{2} h = 6782.4 ft^3\\(3.14) * ( r^2) 20 = 6782.4 ft^3\\r^2 = 108\\r = 10.39$

6 0

3 years ago

Seventy cards are numbered 1 through 70 , one number per card. One card is randomly selected from the deck. What is the probabil

Vanyuwa [196]

Answer:

$Probability = \frac{2}{35}$

Step-by-step explanation:

Given

$Total = 70$

First, we need to list the multiples of 5

$M_5 = \{5,10,15,20,25,30,35,40,45,50,55,60,65,70\}$

Then, multiples of 3 $M_3 = \{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69\}$

Next, is to list out the common elements in both

$M_3\ n\ M_5 = \{15,30,45,60\}$

$n(M_3\ n\ M_5) = 4$

The required probability is then calculated as thus:

$Probability = \frac{n(M_3\ n\ M_5)}{Total}$

$Probability = \frac{4}{70}$

$Probability = \frac{2}{35}$

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3 years ago

Find the average value of the function f(x)=−4sin(x) on the interval [π2,3π2] and determine a number c in this interval for whic

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Answer:

Step-by-step explanation:

The average value theorem sets:

if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that

$\frac{f(b)-f(a)}{b-a}=f'(c)$ , where

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$\frac{4-(-4)}{(3\pi/2)-(\pi/2)}=f'(c)$

$\frac{8}{\pi }=f'(c)$

$f'(x)=-4cos(x)$ ⇒

$f'(c)=-4cos(c)=\frac{8}{\pi }\\c=acos(\frac{-2}{\pi })\\$

c≅130

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3 years ago

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zhannawk [14.2K]

Answer:

I have attached the work to your problem.

Please see the attachment below.

I hope this helps!

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3 years ago

The sum of G and the qoutient of 3 and h

larisa86 [58]

G+(3/h) This is the correct answer!

3 0

3 years ago