Answer:
18,500 , 1 , 1.03
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
f(t) =18,500(1.03)^t
1st blank:
19,055
1.03
3
18,500
2nd blank:
t years
2 years
3 years
1 year
3rd blank:
19,055
3
18,500
1.03
My answer:
Given that: f(t) =18,500*
1st blank:
Initial value when t = 0, so we have:
f(0) =18,500*
So we choose D for 1st blank
2nd and 3rd blank:
Because it's an exponential function f(t) =18,500* , with every value of t increment f(t) increase by a factor of 1.03 . So Every 1 year the number of students who enroll at the university increases by a factor of 1.03
=> 2nd blank: 1
=> 3rd blank: 1.03
Hope it will find you well.
Answer:
AC and AE
Step-by-step explanation:
Those are the only secants in the image shown.
Correct answer is going to be D
Number of students who secured first class in English only is 20
Step-by-step explanation:
- Step 1: Find the number of students who secured first class in English only.
Total number of students who secured first class in English or Maths, T = 80
Number of students who secured first class in Maths, M = 50
Number of students who secured first class in both English and Maths, EM = 10
⇒ Let the number of students who secured first class in English only be x.
Total students with first class, T = M + EM + x
⇒ 80 = 50 + 10 + x
⇒ 80 = 60 + x
∴ x = 80 - 60 = 20
Answer:
The interval of increase of g(x) is 
.
Step-by-step explanation:
The interval of increase occurs when first derivative of given function brings positive values. Let be 
, the first derivative of the function is:
The following condition must be met to define the interval of increase:
The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:
The solution to this inequation is:
Now, the solution to this expression in interval notation is:
