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3 years ago

If the price of a bag of Ritz peanut butter crackers increases from $0.70 to $0.80, what it the percent increase?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

14%

Step-by-step explanation:

To get the percent increase divide 0.8 by 0.7

0.8/0.7 ≈ 1.14285714286

So the percent increase would by about 14 percent

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How do I change this into a reduced fraction

Ivahew [28]

4 over 5 is the correct answer

5 0

3 years ago

Read 2 more answers

I have finals tomorrow lol. If you guys could teach me how to do this you’d be amazing

ddd [48]

2r + 2r + 5 + r + 4r - 3 = 38

9r + 5 - 3 = 38

9r + 2 = 38

9r = 38 - 2

9r = 36

9r/9 = 36/9

r = 4cm

Done!

3 0

3 years ago

What is the volume of the rectangular pyramid shown belown?

Anna35 [415]

9514 1404 393

Answer:

168 cubic inches

Step-by-step explanation:

The formula for the volume of a pyramid is ...

V = (1/3)Bh

where B is the area of the base, and h is the height.

The base is a rectangle, whose are is given by the formula ...

A = LW

A = (8 in)(7 in) = 56 in²

Then the pyramid volume is ...

V = (1/3)(56 in²)(9 in) = 168 in³

The volume of the pyramid is 168 cubic inches.

7 0

3 years ago

How many times as bigger is it? Picture shown above

Mademuasel [1]

2 * 10^2

Divide the first numbers, which are 6 and 3, to get 2. Then, subtract the powers of the exponents, which are 5 and 3, to get 2.

6 0

3 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

4 years ago