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Marat540 [252]
3 years ago
11

the sum of two consecutive integers is -49 write an equation that models this situation and find the values of the two integers

Mathematics
2 answers:
wel3 years ago
8 0
Let n be the 1st number, the 2nd is n+1
But we know that (n) + (n+1) = -49
2n + 1 = - 49
2n = - 49 - 1
2n = -50 and n = - 25 and n+1 = -25 + 1 = -24
the 2 consecutive numbers are - 25 and - 24
hodyreva [135]3 years ago
7 0
Х is the first <span>integer
</span>(x+1) is the second integer

x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25  first integer
-25 + 1 = -24 second integer

Answer: -25 and -24
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In triangle MNP, m = 5 cm, n = 4 cm, and p = 8 cm. Which formula can you use to find P?
charle [14.2K]
Answer:
8² = 4² + 5² - 2(4)(5) cos(P)
which is the third option

Explanation:
The general rule of cosine is:
a² = b² + c² - 2bc*cos(A)

In our triangle:
a is substituted by p = 8 cm
b is substituted by n = 4 cm
c is substituted by m = 5 cm
A is substituted by P which we want to find

Replace the variables in the general equation with the givens as follows:
p² = n² + m² - 2mn*cos(P)
8² = 4² + 5² - 2(4)(5) cos(P)

Hope this helps :)
4 0
3 years ago
Read 2 more answers
Please solve these step-by-step!!
Ierofanga [76]

Answer:

For D. X= 3, or 0 but probably not 0

For the 2nd picture you sent,  x= -2, or -3

Step-by-step explanation:

So for D. you want to make sure you only have 1 Variable, and since we know y=x squared + 7x+5, we subsitute y for what it is equal to.

Then we refine the question, which takes it out to

x squared-3x+5=5 (because the 7x-10x = 3x)

We subtract 5 from both sides which leaves us with x Squared - 3x= 0

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2 years ago
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Answer:

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7 0
2 years ago
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Simora [160]
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7 0
3 years ago
PLEASE HELP the formula m=12,000+12,000rt/12t gives keri's monthly loan payment where t is the annual interest rate and t is the
tatiyna

Answer:

The answer is below

Step-by-step explanation:

The formula m = (12,000 + 12,000rt)/12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length of the loan, in years. Keri decides that she can afford, at most, a $275 monthly car payment. Give an example of an interest rate greater than 0% and a loan length that would result in a car payment Keri could afford. Provide support for your answer.

Answer: Let us assume an annual interest rate (r) = 10% = 0.1. The maximum monthly payment (m) Keri can afford is $275. i.e. m ≤ $275. Using the monthly loan payment formula, we can calculate a loan length that would result in a car payment Keri could afford.

m=\frac{12000+12000rt}{12t}\\ but\ m\leq275, \ and \ r=10\%=0.1\\275= \frac{12000+12000(0.1)t}{12t}\\275= \frac{12000}{12t} +\frac{12000(0.1)}{12t}\\275= \frac{1000}{t} + 100\\275-100= \frac{1000}{t} \\175= \frac{1000}{t} \\175t = 1000\\t= \frac{1000}{175}\\ t=5.72\ years

The loan must be at least for 5.72 years for an annual interest rate (r) of 10%

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