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Marat540 [252]
4 years ago
11

the sum of two consecutive integers is -49 write an equation that models this situation and find the values of the two integers

Mathematics
2 answers:
wel4 years ago
8 0
Let n be the 1st number, the 2nd is n+1
But we know that (n) + (n+1) = -49
2n + 1 = - 49
2n = - 49 - 1
2n = -50 and n = - 25 and n+1 = -25 + 1 = -24
the 2 consecutive numbers are - 25 and - 24
hodyreva [135]4 years ago
7 0
Х is the first <span>integer
</span>(x+1) is the second integer

x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25  first integer
-25 + 1 = -24 second integer

Answer: -25 and -24
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Real numbers can be positive or negative, and include the number zero. They are called real numbers because they are not imaginary, which is a different system of numbers

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3 years ago
Which is a solution of the system of equations shown?
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  D.  (2, 0)

Step-by-step explanation:

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The manager at Ben's Furniture Store is trying to figure out how much to charge for a table that just arrived. If the table was
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3 years ago
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with
soldier1979 [14.2K]

The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

<h3>Probability</h3>

a. Distribution

X ~ N (20 , 6)

b. P(x ≤24)

= P[(x - μ ) / σ  (24 - 20) / 6]

= P(z  ≤0.67)

=  0.74857

=0.7486

Hence:

Probability = 0.7486

c. P(21 < x < 26)

= P[(21 - 26)/ 6) < (x - μ  ) / σ   < (24 - 20) / 6) ]

= P(-0.83 < z < 0.67)

= P(z < 0.67) - P(z < -0.)

=  0.74857- 0.2033

= 0.54527

Hence:

Probability =0.54527

d. Using standard normal table ,

P(Z < z) = 66%

P(Z < 0.50) = 0.66

z = 0.50

Using z-score formula,

x = z×  σ +  μ

x = 0.50 × 6 + 20 = 23

23 Christmas cards

Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

Learn more about probability here:brainly.com/question/24756209

#SPJ1

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