Answer:
C) $573.75
Step-by-step explanation:
We can come up with the equation of this Gross Weekly pay as:

Where P is the amount Larry will get paid, t is the time worked and S is the amount of sales he generated that week. This was derived from the fact that 11.25 is the slope and 0.045S is the y-intercept. By plugging in those values we have:

C) $573.75
Hey!
Hope this helps...
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Generally what I like to do, to solve questions like this is to substitute the given answers into the equation to solve this faster...
Equation: x^2 + 10x + 12 = 36
A.) (-12)^2 + 10(-12) + 12 = 36
144 - 120 + 12 = 36
24 + 12 = 36
36 = 36
(2)^2 + 10(2) + 12 = 36
4 + 20 + 12 = 36
24 + 12 = 36
36 = 36
Since we found the answer with the first try, we already know the correct answer is A.
So...
The Correct answer is: A.) x=-12 or x=2
4ft divided by 2/3ft
4/1 divided by 2/3
4/1 times 3/2 is 12/2 or 6 pieces, 0 remaining.
2 x 6.25
is equal to 12.5 in multiplication
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.