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Colt1911 [192]
3 years ago
15

After the fraction x plus 1 all over 2 minus the fraction x plus 2 all over 3 x have been combined using the least common denomi

nator of 6x, what is the numerator?
Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Let's work out the process to find the numerator:

(x+2)/2 - (x+1)/3x                   Factor using the LCD, 6x

3x(x+2)/6x - 2(x+1)/6x

(3x² + 6x - 2x - 2)/6x

= (3x² + 4x  - 2)/6x

Answer is 3x² + 4x - 2

Hopefully I did this correct, Not to good with math c':

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The sum of two prime numbers is 85. What is the product of these two prime numbers?
hodyreva [135]
Observe that 85 is an odd number. That means, one of the prime numbers must be even to have an odd sum with another odd number. As we know, the only even prime number is 2. Hence, the other number is 83. So, the product of these two prime numbers is 83 x 2 = 166. Thus, the answer is 166<span>. </span>
6 0
3 years ago
If there are 2.54 cm in 1 inch how long is a 36 inch long measuring stick in cm
gayaneshka [121]

Answer:

91.44 cm

Step-by-step explanation:

multipy 2.54 by 36

8 0
3 years ago
The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged
Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

5 0
3 years ago
I need help doing this.
melisa1 [442]

Answer:

6.63

Step-by-step explanation:

6.63324958071

the hundredth spot is the first 3, so you go to the second 3, because its under 5, the second 3 stays the same and doesn't round up to 4.

3 0
3 years ago
I got these wrong help needed plz !!
Lyrx [107]

tiene que sacar la raiz nena

4 0
4 years ago
Read 2 more answers
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