1)1.082*10^9
2)1.496*10^8
3)2.2794*10^8
4)7.784*10^5
5)1.4236*10^9
6)2.867*10^9
7)4.4884*10^9
Hope it helped!
Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
Answer: 3x + 3 = 2x + 1
Answer: 3x + 3 = 2x + 1 <=>3x - 2x = 1 - 3
Answer: 3x + 3 = 2x + 1 <=>3x - 2x = 1 - 3 <=> x = -2
It’s the point where the parabola crosses its axis of symmetry