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3 years ago

When will the distance from A to B be negative?

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

The distance from A to B will be negative when the line is trending downward from left to right.

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A backpack that normally sells for $39 is on sale for 30% off. Find the amount of the sale price

andrey2020 [161]

Answer:

26.13 sale price discount 12.87

Step-by-step explanation:

I do not know how to explain it to where you will understand it but the sale price is 26.13 and the discount it 12.87

Hope that helps

8 0

3 years ago

Please tell me the slope ontercept forn of this equation step by step 11x-4y=32

Afina-wow [57]

Answer:

Gradient is 11/4 and y intercept -8

Step-by-step explanation:

11X -4Y =32

transfer 11x on other side

-4y = -11x +32

multiply all termsby -1 so that coefficient of y is positive

4Y = 11X -32

DIVIDE ALL TERMS BY 4

Y = (11/4)X -8

COMPARE THIS WITH Y=mX +C

GRADIENT m is 11/4 and Y intercept C is -8

Gradient is 11/4 and y intercept -8

4 0

3 years ago

Read 2 more answers

Compute the missing data in the table for the following exponential function f (x) = (one-fourth) Superscript x.

aliina [53]

Answer:

$F(4) = \frac {1}{256}$

Step-by-step explanation:

Given the following mathematical function;

$F(x) = \frac {1}{4^{x}}$

When x = 1

$F(1) = \frac {1}{4^{1}}$

$F(1) = \frac {1}{4}$

When x = 2

$F(2) = \frac {1}{4^{2}}$

$F(2) = \frac {1}{4*4}$

$F(2) = \frac {1}{16}$

When x = 3

$F(3) = \frac {1}{4^{3}}$

$F(3) = \frac {1}{4*4*4}$

When x = 4

$F(4) = \frac {1}{4^{4}}$

$F(4) = \frac {1}{4*4*4*4}$

$F(4) = \frac {1}{256}$

When x = 5

$F(5) = \frac {1}{4^{5}}$

$F(5) = \frac {1}{4*4*4*4*4}$

$F(5) = \frac {1}{1024}$

8 0

3 years ago

The second term from the end of the A.P. 5.8. 11,......47 is

enyata [817]

D = -(8-5) = -3
a = 47
an = a + (n-1)d = 47 + (-3) = 47 - 3 = 44

7 0

3 years ago

What is the asymptote of the graph of f(x)=5x−1?

Marina86 [1]

The asymptotes of the graph of $f(x) = \frac{5}{x - 1}$ are as follows:

Vertical: x = 1.

Horizontal: y = 0.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{5}{x - 1}$

For the vertical asymptote, we have that:

$x - 1 = 0 \rightarrow x = 1$ .

For the horizontal asymptote, we have that:

$y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0$ .

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

3 0

1 year ago