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3 years ago

When will the distance from A to B be negative?

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

The distance from A to B will be negative when the line is trending downward from left to right.

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How to find the value of a+b+c given that a=4,b=3 and c= -2

Alexus [3.1K]

Answer: 5

Step-by-step explanation: 4 + 3 + -2 = 5

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3 years ago

The area of this parallelogram is 120 ft. Find the value of h

julsineya [31]

are you going to show a picture??? its impossible to answer otherwize

4 0

3 years ago

Find the midpoint of the line segment JK if j (4,6) and k(0,-4)

Snowcat [4.5K]

Answer:

$(2,1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define points

J (4, 6)

K (0, -4)

Step 2: Find midpoint

Substitute: $(\frac{4+0}{2},\frac{6-4}{2})$
Add/Subtract: $(\frac{4}{2},\frac{2}{2})$
Divide: $(2,1)$

4 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

8x+4(x-3)=4(6x+4)-4 please help

kvasek [131]

Answer:

x = -2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x + 4(x - 3) = 4(6x + ) -4

8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)

8x + 4x + -12 = 24x + 16 + -4

(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)

12x + -12 = 24x + 12

12x -12 = 24x + 12

Step 2: Subtract 24x from both sides.

12x -12 -24x = 24x + 12 -24x

-12x -12 = 12

Step 3: Add 12 to both sides.

-12x - 12 + 12 = 12 + 12

-12x = 24

Step 4: Divide both sides by -12.

-12x/-12 = 24/-12 x = -2

HOPE THIS HELPED!!!

5 0

3 years ago