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OLga [1]
3 years ago
14

Round 399,713 to the nearest thousand

Mathematics
1 answer:
solniwko [45]3 years ago
3 0
399,713 rounded to the nearest thousand would be <span>400,000

Hope I Helped!!! :-)

</span>
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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
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Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.3898 = 38.98% probability that there will be 4 failures

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Step-by-step explanation:

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