Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
Answer:
It's the first option.
Step-by-step explanation:
It is turned down so the one half is negative (-1/2)
parabola will be in the form of a(x-h)^2 + k. (-h, k) is your vertex, in this case that is (15,25). so in the equation, you will have
-1/2(x-15)^2 + 25. first one.
Hope this helps!
29 ...................................................................................................
Answer:
1 is congruent 2 is neither and 3 is similar
Step-by-step explanation:
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