Answer:

mass = 3.645 g
volume = 9×9×9
= 729 cm³
density = 3.645/729
= 0.005 gcm^-3
Step-by-step explanation:
the volume is 729 cm³ cause the given height is 9cm and it is a cube. cube has equal sides so their lengths are the same.
volume = length × height × width
Factor by grouping.
(7x+2)(x-2) I think not sure
9514 1404 393
Answer:
-361
Step-by-step explanation:
Your calculator can tell you the result. It is -361.
Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.
-3[2/6+8{-9/3(8-5*3)-6}]
= -3[2/6+8{-9/3(8-15)-6}]
= -3[2/6+8{-9/3(-7)-6}]
= -3[2/6+8{-3(-7)-6}]
= -3[2/6+8{21-6}]
= -3[2/6+8{15}]
= -3[1/3+8{15}]
= -3[1/3+120]
= -3[361/3]
= -361
Answer:
Step-by-step explanation:
9) PQR Is an isosceles triangle
=> ∠PRQ = (180° - x)/2
PRS is an isosceles right triangle
=> ∠PRS = 45°
Have: ∠PRS + ∠PRQ = 115°
=> 
=> 180 - x = (115 - 45).2 = 140
<=> x = 180 - 140 = 40
10) ABD is an isosceles right triangle => ∠ABD = 45°
BCD is an equilateral triangle => ∠CBD = 60°
have: x = ∠ABD + ∠CBD = 45° + 60° = 105°
11) have: x = y (2)
PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40
QTS is an isosceles triangle => ∠TQS = 180 -2x
QRS is an isosceles triangle => ∠RSQ = y
have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)
(1)(2) => 
=> x + y = 80
12) EFJ Is an equilateral triangle => ∠FJE = 60
∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle
=> 60 = 2.∠JHF => ∠JHF = 30°
∠JHF is the outer angle of the triangle FHG
=> 30° = 2x
<=> x = 15°
Perimeter = (2 × Length) + (2 × Width)
If the length is dependent on the width (because the length is 10 more than the width), we can say that L = W + 10.
To find the answer to the Peri, we have to find out what the W is first.
184 = 2(W + 10) + 2W
184 = 2W + 20 + 2W
184 = 4W + 20
184 - 20 = 4W = 164
164 ÷ 4 = W
41 = W
We have found out width. Our length is W + 10, so L = 41 + 10 = 51
W = 41 and L = 51