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KATRIN_1 [288]
2 years ago
11

Is y=3x+b a linear relationship

Mathematics
1 answer:
Nataly_w [17]2 years ago
5 0
Yes it is a linear relationship
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A cube made of an unknown material has a height of 9 cm. The mass of this cube is 3.645 grams. What is the density of this cube?
ehidna [41]

Answer:

density =  \frac{mass}{volume}

mass = 3.645 g

volume = 9×9×9

= 729 cm³

density = 3.645/729

= 0.005 gcm^-3

Step-by-step explanation:

the volume is 729 cm³ cause the given height is 9cm and it is a cube. cube has equal sides so their lengths are the same.

volume = length × height × width

8 0
2 years ago
Hey, I've been extremely confused with problems like :7x²-12x-4
bonufazy [111]
Factor by grouping.

(7x+2)(x-2) I think not sure
4 0
3 years ago
Bodmass<br><br>-3[2/6+8{-9/3(8-5*3)-6}]​
Vadim26 [7]

9514 1404 393

Answer:

  -361

Step-by-step explanation:

Your calculator can tell you the result. It is -361.

Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.

  -3[2/6+8{-9/3(8-5*3)-6}]​

  = -3[2/6+8{-9/3(8-15)-6}]​

  = -3[2/6+8{-9/3(-7)-6}]​

  = -3[2/6+8{-3(-7)-6}]​

  = -3[2/6+8{21-6}]​

  = -3[2/6+8{15}]

  = -3[1/3+8{15}]

  = -3[1/3+120]

  = -3[361/3]

  = -361

8 0
2 years ago
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
2 years ago
The length of a rectangle is 10 meters more than the width. If the perimeter is 184 meters, what are the length and the width?
Brilliant_brown [7]
Perimeter = (2 × Length) + (2 × Width)

If the length is dependent on the width (because the length is 10 more than the width), we can say that L = W + 10.

To find the answer to the Peri, we have to find out what the W is first.

184 = 2(W + 10) + 2W
184 = 2W + 20 + 2W
184 = 4W + 20
184 - 20 = 4W = 164
164 ÷ 4 = W
41 = W

We have found out width. Our length is W + 10, so L = 41 + 10 = 51

W = 41 and L = 51


3 0
2 years ago
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