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ira [324]
3 years ago
8

What is the probability that a randomly number from 20 to 30 is divisible by 3 and then divisible by 12 after replacing first

Mathematics
1 answer:
tester [92]3 years ago
7 0
Probability of divisibility by3=4/11
probability of divisibility by 12 =1/11
probability of divisibility by 12 and 3=4/11×1/11
answer is 4/121

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Work out each map scale as a map ratio
vampirchik [111]
1:500000
1cm:500000cm

2:250000
2cm:250000cm
1cm:125000cm

To get this you convert the km into cm as it is easier and then it becomes something like this 2cm : 250000cm
then divide or half to get to the simpler form like this 2cm divided by 2=1cm and 250000cm divided by 2= 125000cm 
then put into ratio is 1:125000

6 0
2 years ago
In a class 2/5 of the children are boys.What fraction are girls
Bas_tet [7]

Answer:

3/5

Step-by-step explanation:

Self explanatory.

3 0
1 year ago
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Find the slope (-2,-4) (2,4)
Alex

Answer:

8 over 4

Step-by-step explanation:

5 0
3 years ago
Solve the system of equations. Show ALL your work. Put your answer in the form of an ordered pair (x, y)
stiv31 [10]
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation. 
                         -4(2y) + 11y = 15
                         -8y + 11y = 15
                                   3y = 15   ; y = 5
Substitute this value of y to either the first or second equation.
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6 0
3 years ago
Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe
icang [17]

Answer:

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

  h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

  h(-1) = 8(-1)²(-1-3) = -32

  h(0) = 8(0)(0-3) = 0

  h(2) = 8(2²)(2 -3) = -32

  h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

  • (-1, -32) absolute minimum
  • (0, 0) relative maximum
  • (2, -32) absolute minimum
  • (+∞, +∞) absolute maximum

_____

Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

5 0
3 years ago
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