From A to B...
distance formula : sqrt ((x2 - x1)^2 + (y2 - y1)^2
(-3,1)....x1 = -3 and y1 = 1
(1,3)....x2 = 1 and y2 = 3
sub
d = sqrt ((1 - (-3)^2 + (3 - 1)^2
d = sqrt ((1 + 3)^2 + 2^2
d = sqrt (4^2 + 2^2)
d = sqrt (16 + 4)
d = sqrt 20
d = 4.47 miles...so from A to B, it was 4.47 miles
from B to C
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2
(1,3)....x1 = 1 and y1 = 3
(5,-1)...x2 = 5 and y2 = 1
sub
d = sqrt ((5 - 1)^2 + (-1 - 3)^2
d = sqrt ((4^2 + (-4^2)
d = sqrt (16 + 16)
d = sqrt 32
d = 5.66......but keep in mind, he only drove half-way...so 5.66/2 = 2.83 miles
for a total of : 4.47 + 2.83 = 7.3 miles <===
Respuesta:
a = 82; b 164
Explicación paso a paso:
a = 1 / 2b - - - (1)
a gana 66 = a + 66
b = b - 90
a = 2b
a + 66 = 2 (segundo - 90) - - - (2)
Ponga a = 1 / 2b en (2)
1 / 2b + 66 = 2 (b-90)
0.5b + 66 = 2b - 180
0.5b - 2b = - 180 - 66
-1,5b = - 246
b = 164
a = 1 / 2b
a = 1/2 * 164
a = 82
Answer:
D because mean is the subtraction of the biggest number and the smallest. so 17-8=9
Answer:
Step-by-step explanation:
-10 + 20 i
Answer:
Angle of inclination = 16.7°; normal reaction = 93.96N
Step-by-step explanation:
Frictional force is known as force of opposition that tends to oppose the motion of a body (moving force Fm) placed on a rough surface. Frictional force Ff is expressed as;
Ff = nR where;
n is the coefficient of static friction
R is the normal reaction
From the formula;
n = Ff/R
Where Ff = Fm = Weight of the object × sinθ i.e Wsinθ
and R = Wcosθ
n = wsinθ/wcosθ
n = sinθ/cosθ
n = tanθ
Given µs = 0.3
0.3 = tanθ
θ = arctan0.3
θ = 16.7°
Angle of inclination is 16.7°
The normal reaction at B if the ladder is on the verge of slipping can be gotten using the expression;
R = wcosθ
R = mgcosθ where
m is the mass of the ladder = 10kg
g is the acceleration due to gravity = 9.81m/s
R = 10×9.81×cos16.7°
R = 93.96N
