Answer: 0.5898
Step-by-step explanation:
Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .
We assume that,
The probability that .J. Redick makes any given free throw =0.901 (1)
Free throws are independent.
So it is a binomial distribution .
Using binomial probability formula, the probability of getting success in x trials :

, where n= total trials
p= probability of getting in each trial.
Let x be binomial variable that represents the number of a=makes.
n= 14
p= 0.901 (from (1))
The probability that he makes at least 13 of them will be :-

![=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898](https://tex.z-dn.net/?f=%3D%5E%7B14%7DC_%7B13%7D%280.901%29%5E%7B13%7D%281-0.901%29%5E1%2B%5E%7B14%7DC_%7B14%7D%280.901%29%5E%7B14%7D%281-0.901%29%5E0%5C%5C%5C%5C%3D%2814%29%280.901%29%5E%7B13%7D%280.099%29%2B%281%29%280.901%29%5E%7B14%7D%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_n%3D1%5C%20%5C%26%5C%20%5EnC_%7Bn-1%7D%3Dn%20%5D%5C%5C%5C%5C%5Capprox0.3574%2B0.2324%3D0.5898)
∴ The required probability = 0.5898
On the first play the Tigers lost yards. The number of yards they lost was 3 yards. We know this because the integer that is shown is -3. This negative value is move to the left or down on the number line. It represents a negative change, and in football it is a loss of yards.
Okay so first u would do 37.5/100 * x/87.5
cross multiply get a result of 3.2815
add that to 8.75
end up with 12.0315
Answer:
Step-by-step explanation:
Trick question. Good to know.
0 is the closest 100.
33 will round to 0
Answer:

Step-by-step explanation:
<u>Probability</u>
The simple probability of a random event can be calculated as the ratio between the possible favorable cases and the total possible cases.
The pie chart shows the number of books in Hero's library grouped by category.
The total number of books is 14 + 10 + 4 + 2 = 30
The number of romance books is 2
Thus, the probability of randomly choosing a romance book out of the total books is:

Simplifying:

This corresponds to the first option