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yuradex [85]
4 years ago
15

What is the quotient of 9 and 3

Mathematics
2 answers:
dimaraw [331]4 years ago
4 0

Answer:

3

Step-by-step explanation:

quotient of 9 and 3

9/3 = 3

Vladimir [108]4 years ago
4 0

Answer:

9/3=3

Step-by-step explanation:

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
LekaFEV [45]

We have been given a graph that involves Real axis and Imaginary axis.

From that graph we have to choose correct line segment which joins complex numbers 2+2i and -1+3i.


We know that if complex number is (a+bi) then real part "a" is always plotted along x-axis and the imaginary part "b" is always plotted along y-axis just like point (a,b) on x-y graph.

So 2+2i means point (2,2) on x-y graph which is at point B.

similarly -1+3i means point (-1,3) which will be at point A.

So the line segment joining them will be AB

Hence final answer is the line segment AB.

4 0
3 years ago
Read 2 more answers
Help me pleases find what is Yz
ohaa [14]

Answer:

34

Step-by-step explanation:

3n + 7 = 5n -11 (because of SAS)

-2n = -18

n = 9

yZ = 3(9)+7 = 34

3 0
3 years ago
Read 2 more answers
An amusement park reduced it's admission price to $15.50 per day, but now charges $1.50 per ride. Mark has $26 to spend on admis
gtnhenbr [62]
15.50+1.50x =26
1.50x = 10.50
x = 7
answer: he can ride 7 in one day
4 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
4 years ago
The diameter of the Moon is about 3,476 km the distance from Earth to the Moon is about 384,400 km about how many moons could be
konstantin123 [22]

Answer:

roughly 100 moons could fit between the earth and the moon.

Step-by-step explanation:


6 0
3 years ago
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