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3 years ago

Write the standard equation of a circle with center (0, 3) passing through the point (2, 5)

Mathematics

1 answer:

marysya [2.9K]3 years ago

3 0

The equation is x² + (y-3)²=8

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Solve for X -6.9<8.1-1.5x

notka56 [123]

Step-by-step explanation:

-6.9<8.1-1.5x

-9.6-8.1<-1.5x

-15<-1.5x

-1.5x>-15

x>10

8 0

3 years ago

The axis of symmetry for the function f(x) = −x2 − 10x + 16 is x = −5. What are the coordinates of the vertex of the graph?

Vesna [10]

The vertex of this function is ( -5 , 41)

6 0

3 years ago

Read 2 more answers

Explain why any number less than 12.5 and greater than or equal to 11.5 would round to 12 when rounded to the nearest whole numb

n200080 [17]

Because you round to the another number up

5 0

3 years ago

If A is the area of a square measured in square inches and s is the square's side length measured in inches, then the square's s

motikmotik

Answer:

g(3.5), g(26.92)

g(3.5)=3.5^2, g(26.92)=26.92^2

5 0

3 years ago

In 2015 as part of the General Social Survey, 1289 randomly selected American adults responded to this question:

Radda [10]

Answer:

B (0.312, 0.364)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

1289 randomly selected American adults responded to this question. This means that $n = 1289$ .

Of the respondents, 436 replied that America is doing about the right amount. This means that $\pi = \frac{436}{1289} = 0.3382$ .

Determine a 95% confidence interval for the proportion of all the registered voters who will vote for the Republican Party. 

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3382 - 1.96\sqrt{\frac{0.3382*0.6618}{1289}} = 0.312$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3382 + 1.96\sqrt{\frac{0.3382*0.6618}{1289}} = 0.364$

The 95% confidence interval is:

B (0.312, 0.364)

5 0

3 years ago