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valentina_108 [34]
3 years ago
12

The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

number of E.coli bacteria cells per 100 mL of water and t represents the time, in years, that has elapsed.
A(t)=136(1.123)^4t

Based on the model, by approximately what percent does the number of E.coli bacteria cells increase each year?


A.

60%

B.

59%

C.

41%

D.

40%
Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:c 41 %

Step-by-step explanation:

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I need some help with this one
Mrac [35]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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What is 11.52/128 show your work
grandymaker [24]

Answer:

The answer is

<h2>9/100</h2>

Step-by-step explanation:

11.5/128

First convert the decimal to an improper fraction

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11.52 =  \frac{288}{25}

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\frac{288}{25}  \div 128

Change the division sign to multiplication sign and reverse the second number

That's

\frac{288}{25}  \times  \frac{1}{128}

Simplify

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Hope this helps you

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