Question

What are the zero(s) of the function f(x)=4x2-36x over x-9?

Answer 1

F(x) = (4x^2 - 36x) / (x-9)
0 = 4x * (x-9) / (x-9)
0 = 4x

x=0
hope this helps

Answer 2

Answer:

x=0 is the zero of the given function

Step-by-step explanation:

$f(x) = \frac{4x^2-36x}{x-9}$

To find zeros of the function we replace f(x) with 0

then we solve for x

$0= \frac{4x^2-36x}{x-9}$

Now we factor the numerator 4x^2 -36x

$0= \frac{4x(x-9)}{x-9}$

Cancel out x-9 at the top and bottom

0=4x (divide by 4 on both sides)

x=0

So x=0 is the zero of the given function