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Amiraneli [1.4K]
3 years ago
9

Simplify the expression (8x^3y^2/4a^2b^4)^-2

Mathematics
1 answer:
icang [17]3 years ago
3 0
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
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Ayanna is 3 years older than Brittany. The sum of 3 times Brittany's age and 2 times Ayanna's age is 76. How old are Ayanna and
Alex_Xolod [135]
Ayanna is 17 and Brittany is 14.

To find this, let's write two equations using the given information.

a = b + 3
3b + 2a = 76

Now, just substitute the first equation into the second and solve.

3b + 2(b + 3) = 76
3b + 2b + 6 = 76
5b = 70
b = 14

If Brittany is 14, then Ayanna is 3 years older at 17.
7 0
3 years ago
1/6d + 2/3 = 1/4(d-2) how to solve
natita [175]
Greetings!

Solve for d.
1/6d + 2/3 = 1/4(d-2)
Distribute the Parenthesis.
1/6d + 2/3 = 1/4*d+1/4*-2
1/6d + 2/3 = 1/4d+1/4*-2/1
1/6d + 2/3 = 1/4d-2/4
Reduce.
1/6d + 2/3 = 1/4d-1/2
Add -2/3 to both sides.
(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)
Simplify.
1/6d=1/4d-3/6-4/6
1/6d=1/4d-7/6
Add -1/4d to both sides.
(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)
Simplify.
2/12d)-3/12d=-7/6
-1/12d=-7/6
Divide both sides by -1/12.
(-1/12d)/-1/12=(-7/6)/-1/12
Simplify.
d=(-7/6)*-12/1
d=84/6
Reduce.
d=14/1
d=14

Hope this helps.
-Benjamin
7 0
3 years ago
What is the solution to q/-7=6?
marta [7]

Answer:

q in (-oo:+oo)

q/(-7) = 6 // - 6

q/(-7)-6 = 0

-1/7*q-6 = 0 // + 6

-1/7*q = 6 // : -1/7

q = 6/(-1/7)

q = -42

q = -42

Hope I was helpful! :)

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3 years ago
Please help, it's urgent!
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