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Amiraneli [1.4K]

3 years ago

9

Simplify the expression (8x^3y^2/4a^2b^4)^-2

1 answer:

icang [17]3 years ago

3 0

Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A

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Hi! Algebra two question, rational exponents.

ivanzaharov [21]

Simplifying $\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$ we get $\left(x+4y\right)}$

Step-by-step explanation:

We need to simplify:

$\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$

For solving, we will first simplify the terms inside the exponent and then solve exponent

First Solving: $\left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}$

Using the formula: $(a^2+2ab+b^2)=(a+b)^2$

$\left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}\\\left((x)^2+2(x)(4y)+(4y)^2\right)}.\left(x+4y\right)}\\\left(x+4y\right)^2}.\left(x+4y\right)}$

Using exponent rule:

$a^m.a^n=a^{m+n}$

$\left(x+4y\right)^{2+1}}\\\left(x+4y\right)^3}$

Now,

$(\left(x+4y\right)^3})^{\frac{1}{3}}\\Simplifiying:\\\left(x+4y\right)}^{\frac{3}{3}}\\\left(x+4y\right)}$

So, simplifying $\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$ we get $\left(x+4y\right)}$

Keywords: Solving Rational exponents:

Learn more about Solving Rational exponents at:

#learnwithBrainly

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