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irinina [24]
3 years ago
10

The function of g(x)=8^2-48+65 written in vertex form is g(x)= 8(x-3)^2-7 what is the vertex of g(x)

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0
The vertex is where g(x) = 0 
i.e. where 8(x^3)^2-7 is equal to x 

who wrote this question, there aRE OBVIOUS errors. 
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A non-stop train leaves Lahore at 4:00 pm and reaches Karachi at 10:00 am the next day. The speed of the train was 70 km/hour. F
denis23 [38]

Calculate the number of hours between 4 PM and 10 AM:

4 PM to 4 AM is 12 hours.

4 AM to 10 AM is 6 hours

Total hours is 12 + 6 = 18 hours.

18 hours x 70 km/hr = 1,260 km total.

4 0
3 years ago
A deep sea diver is 4.5m below the water level At what depth he is now ? At what height is he now
oee [108]

Answer:

Step-by-step explanation:

Below the sea level should be mentioned by negative value

So, It is  =  - 4.5

7 0
3 years ago
If SP:100, CP:80 find is profit or lost percent?​
TiliK225 [7]

Step-by-step explanation:

profit =20 rs

profit% = 20/80*100

=25%

3 0
3 years ago
Read 2 more answers
The slope of a line is 7/10 . One point on the line has coordinates (1, 2). Which ordered pair represents another point on the l
mash [69]
(x,y)

y=mx+b
m=slope
b=yintercept
slope=7/10
one point is (1,2) or x=1, then y=2
find b
y=7/10x+b
2=7/10(1)+b
2=7/10+b
minus 7/10 both sides
1 and 3/10=b
13/10=b
y=7/10x+13/10
input values for x and get values for y
one point is (0,13/10)
7 0
3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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