Answer:
pls help with what brainlics
Answer:
Step-by-step explanation:
Let's put the data as below:
n1=15 x1=2.8 s1=1.6 and s1²=2.56
n2=19 x2=2.4 s2=1.7 and s2²=2.89
alpha= 0.05
To test the hypothesis:
H0= There is no sufficient evidence that low income household have fewer children
H1=There is sufficient evidence that low income household have fewer children
Assume that population variances are equal.
the t-static for two samples,
~t with min (n1-1,n2-1)df
The pooled variance estimate Sp equals:

Sp²=2.7456
Sp=1.65699
Degrees of freedom=n1+n2-2=32
Under null hypothesis:


The critical value ttab=2.0369 for alpha=0.05
So we reject our null hypothesis H0
So there is sufficient evidence that low income households have fewer children than high income households
Answer: y = one twelfth(x + 2)2
Step-by-step explanation:
just did the test
Answer:
(-1, 6)
Step-by-step explanation:
The midpoint is the halfway point. So, if M is the midpoint of PQ, then simply take the distance between your P and M co-ordinates and apply that one more time to get to Q.
Your x value at point M is 5, and your x value at point P is 11.
11 and 5 are 6 units apart.
Since M is in the middle of P and Q, M is therefore 6 units apart from both P and Q on the x-axis, so we can subtract 6 from 5 to find Q's x co-ordinate of -1.
Your y value at point M is -2, and your y value at point P is -10.
-10 and -2 are 8 units apart.
Add 8 to M to find your y co-ordinate at point Q of 6.
Your Q point is at (-1, 6).