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mr_godi [17]
3 years ago
8

How do you simplify radical 32

Mathematics
1 answer:
EleoNora [17]3 years ago
4 0
\sqrt{32}=  \sqrt{16*2}= \sqrt{16}* \sqrt{2}=4 \sqrt{2}
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Masteriza [31]

Answer:

(2,-5) and (2,1).

Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is the radius.

(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

(4)^2+(y+2)^2=25

(y+2)^2=25-16

(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

Therefore, the required points are (2,-5) and (2,1).

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IrinaVladis [17]

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Answer:

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5 (2/3) x = 11 (1/3)

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Step-by-step explanation:

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seropon [69]

Answer:

x=3

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3(2x+3)=27

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