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4 years ago

A number plus 8 is greater than 11

Mathematics

2 answers:

Nat2105 [25]4 years ago

5 0

Answer:

it could be 4 or a number greater than 4

bija089 [108]4 years ago

3 0

Answer:

n+8 > 11

Step-by-step explanation:

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zheka24 [161]

Answer:

1.90.93

2.90.27

Step-by-step explanation:

5 0

3 years ago

write an equation in slope intercept form for the line that passes through (4, -4) and is parallel to 3x+4x=2y-9

photoshop1234 [79]

Answer:

$\large\boxed{y=\dfrac{7}{2}x-18}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

Convert the equation of a line 3x + 4x = 2y - 9 to the slope-intercept form:

$3x+4x=2y-9$

$7x=2y-9$ add 9 to both sides

$7x+9=2y$ divide both sides by 2

$\dfrac{7}{2}x+\dfrac{9}{2}=y\to y=\dfrac{7}{2}x+\dfrac{9}{2}$

Parallel lines have the same slope. Therefore we have the equation:

$y=\dfrac{7}{2}x+b$

Put the coordinates of the point (4, -4) to the equation:

$-4=\dfrac{7}{2}(4)+b$

$-4=7(2)+b$

$-4=14+b$ subtract 14 from both sides

$-18=b\to b=-18$

Finally we have the equation:

$y=\dfrac{7}{2}x-18$

8 0

4 years ago

A dog collar was originally priced at $5 but went on sale for 20% off. If Vince bought the dog collar and paid 9% sales tax, how

Vlada [557]

Answer:$4.36

Step-by-step explanation:

5(0.8)= 4

4(1.09) = $4.36

3 0

3 years ago

Thirty-seven percent of all Americans drink bottled water more than once a week (Natural resources Defense Council, December 4,

lesantik [10]

Answer:

a) The sampling distribution for n=540 has a mean sample proportion of p=0.37 and a standard deviation of σs=0.0208.

b) probability = 0.99998

d) probability = 0.99874

e) You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

Step-by-step explanation:

a) We have a known population proportion π=0.37 and we have to describe the sampling distribution when the sample size is n=540.

The mean sample proportion is expected to be the same as the population proportion:

$\bar p = \pi = 0.37$

The standard deviation of the sampling will be the population standard deviation divided by the square root of the sample size:

$\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{540}}=\sqrt{0.000431667}=0.0208$

Then, we can say that the sampling distribution will have a p=0.37 and a standard deviation σs=0.0208.

b) We have to calculate the probability that the sample proportion will be within 0.09 of the population proportion.

We can calculate the z-value as:

$z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0208}=4.3269\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0208}=-4.3269$

As the distribution is symmetrical, we can calculate the probabilty that he sample proportion will be within 0.09 of the population proportion as:

$P(|p-\bar p|$

probability = 0.99998

d. Now the sample is smaller (n=300), so the standard deviation of the samping distribution:

$\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.37*0.63}{300}}=\sqrt{0.000777}=0.0279$

We have to recalculate the z-scores:

$z_1=\dfrac{p_1-\bar p}{\sigma_s}=\dfrac{0.09}{0.0279}=3.2258\\\\\\z_2=\dfrac{p_2-\bar p}{\sigma_s}=\dfrac{-0.09}{0.0279}=-3.2258$

And the probability is:

$P(|p-\bar p|$

probability = 0.99874

e. The increase in sample size is 80%

$\Delta n\%=\dfrac{n_1}{n_2}-1=\dfrac{540}{300}-1=1.8-1=0.8=80\%$

and the increase in probability is 0.12%

$\Delta P\%=\dfrac{P_1}{P_2}-1=\dfrac{0.99998}{0.99874}-1=1.0012-1=0.0012=0.12\%$

You gain 0.12% in probability for an increase of 80% in sample size.

The increase in sample size is not justified by the increase in probability, for this margin of error (Δp=0.09).

7 0

3 years ago

Can you please help me with this question

cestrela7 [59]

8,9 2,4 1,8 hope this may help!!

8 0

3 years ago

Read 2 more answers