Find mQPR. If mQPS=40,mRPS=8x+7,mQPR=9x+16
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D(7, 3), E(8, 1), and F(4, -1)
We calculate the squared distances between the points:
Since we have a right triangle with hypotenuse DF.
Subtract 3 from both sides,
Let x = X and y - 3 = Y
Then,
So, we have shifted the origin to a point (0, 3).
This is an odd function and the graph of an odd function is symmetrical about the origin.
That is, symmetrical about X = 0, Y = 0
Symmetrical about x = 0,, y - 3 = 0
Symmetrical about x = 0, y = 3.
Hence, the graph is symmetrical about the point (0, 3).