Yes, these are equivalent
Answer:
(A)
(B)
Step-by-step explanation:
(A)
we are given
Firstly, we will find few terms
so, we will get terms as
5, 7 , 9 , 11
we can see that this is arithematic sequence
First term =5
common difference =d=7-5=2
now, we can use nth term formula
now, we can plug values
(B)
we can plug n=10
Answer:
The answer is 3(2x + 3)
Step-by-step explanation:
6(3x + 3) - 3(4x – 2)
Multiply (3x + 3) by 6 and (4x – 2) by (-3) we get,
6 (3x + 3) = 18x + 3
(-3) (4x – 2) = -12x + 6
Now, Simply
18x + 3 – 12x + 6
6x + 9 = 3(2x + 3)
Thus, The answer is 3(2x + 3)
<u>-TheUnknownScientist 72</u>
Answer:
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Class 11
>>Physics
>>Units and Measurement
>>Errors in Measurement
>>You measure two quantities ...
Question
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You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for
AB
as
Medium
Solution
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Correct option is
D
1.4m±0.2m
Here, A=1.0m±0.2m, B=2.0m±0.2m
AB=(1.0m)(2.0m)=2.0m
2
AB
=
2.0m
=1.414m
Rounding off to two significant figures, we get
AB
=1.4m
AB
ΔAB
=
2
1
(
A
ΔA
+
B
ΔB
)=
2
1
(
1.0
0.2
+
2.0
0.2
)=
2
0.3
Δ
AB
=
2
0.3
×
AB
=
2
0.3
×1.414=0.212m
Rounding off to one significant figure, we get
Δ
AB
=0.2m
The correct value for
AB
is 1.4m±0.2m
Answer:
5 blocks
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to solve for AC
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
AC² = AB² + BC² ← substitute values
AC² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )
AC = 
= 5
