Question

Which point lies on the circle represented by the equation (x−1)2+(y−3)2=72? f (8, 3) g (-1, 4) h (1, 3) j (0, 7)?

Answer 1

For this case, the equation of the circle is given by:
$(x-1) ^ 2 + (y-3) ^ 2 = 7 ^ 2$
 We evaluate the points to see which ones satisfy the equation.
 We have then:
 For (8, 3):
$(8-1) ^ 2 + (3-3) ^ 2 = 7 ^ 2$
  Rewriting we have:
$(7) ^ 2 + (0) ^ 2 = 7 ^ 2 7 ^ 2 = 7 ^ 2$
 We observe that this point satisfies the equation and therefore, is in the circle.
 Answer:
 A point lies on the circle represented by the equation $(x-1) ^ 2 + (y-3) ^ 2 = 7 ^ 2$ is:
 f (8, 3)