The answer would be 6x(5x-2).
Since both terms have x in them, x will be apart of your answer.
The GCF of 12 and 30 is 6.
So you can factor out 6x from both terms.
Hope this helps!
She will be 75 minutes late because you take the 15 minutes per stop and multiply it by the five stops.
Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Answer:
10 ring boxes
Step-by-step explanation:
First, we need to calculate the total surface area of each cube ring boxes
The surface area of each square boxes = 6L²
Given that L =1.5inches
Total surface area = 6(1.5)²
Total surface area = 6(2.25)
Total surface area = 13.5in²
<em>Since the question is incomplete. Let us assume the total surface area of the shipping box is 135in²</em>
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Number of ring boxes he can ship = 135/13.5
Number of ring boxes he can ship = 10
Hence the number of ring boxes he can ship is 10 ring boxes
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<u><em>NB: The total surface area of the shipping box was assumed</em></u>
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