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UkoKoshka [18]
3 years ago
12

How do you solve 5(2) to the power of x = 5x+4

Mathematics
1 answer:
Digiron [165]3 years ago
5 0
X + -12 = 5x + 4

Reorder the terms:
-12 + x = 5x + 4

Reorder the terms:
-12 + x = 4 + 5x

Solving
-12 + x = 4 + 5x
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A baby weights 18 pounds at her four month appointment. Six months later she weights 24 pounds. By what percentage did the baby’
Anna11 [10]

Answer: 25%

Step-by-step explanation:

Given : Previous baby's weight = 18 pounds

New baby's weight =  24 pounds.

Increase in weight = New weight -Previews weight

=24 pounds - 18 pounds  =6 pounds

Percentage increase in baby's weight ==\dfrac{\text{Increase in baby's weight}}{\text{previous weight}}\times100

\\\\=\dfrac{6}{24}\times100=25\%

Hence, the percentage increase in baby's weight = 25%

4 0
3 years ago
Find the derivative of the function. y = √(11x + √(11x + (√11x)))
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Its long man, and complex haha... is this for a class?

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3 years ago
Find the HCF of 27, 63, 54 using prime factorization method.
Step2247 [10]

Answer:

27 = 3 , 3, 3

63= 3 , 3, 7

54= 3 , 3, 3, 2

HCF OF 27, 63 AND 54 = 3 X 3 = 9

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7 0
3 years ago
What is 5 divided by 25
disa [49]

Answer:

0.2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
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