The conditions are suitable to be modelled using a binomial distribution.
p=0.43
n=15
x=5
P(x=5)
=C(15,5)*0.43^5*(1-0.43)^(15-5)
=15!/(5!(15-5)!)*0.43^5*(1-0.43)^(15-5)
=3003*0.0147008*0.003620333
=0.1598
8 is the answer cuz if you dive and all that
From the given problem, I gather that there are only two groups of forces. These are:
13 lb, 35 lb, resultant force 30 lb
20 lb, 15 lb, resultant force 25 lb
We use the pythagorean theorem to determine if the three forces are grouped correctly, such that the resultant force is the hypotenuse.
Resultant Force = √(a² + b²)
So, for the first group,
30 ? √(13² + 35²)
30 ≠ 37.33
Thus, the first group does not pull at right angles to each other.
For the second group,
25 ? √(20² + 15²)
25 = 25
Thus, the second group does pull at right angles to each other.