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kramer
4 years ago
9

Y = e^(lnx)² Find the derivative

Mathematics
1 answer:
Nitella [24]4 years ago
8 0
\large {d \over dx} \;\;e^{\ln^2 (x)} =e^{\ln^2 (x)} \cdot {d \over dx}\;\;\ln^2 (x)
\\
\\\large =e^{\ln^2 (x)} \cdot 2 \ln(x)\; {d \over dx} \;\;\ln(x)=e^{\ln^2 (x)} \cdot {2 \ln(x)\over x}
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