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CaHeK987 [17]
3 years ago
8

How many smaller rectangles are there in an area model that represents 27 times 83 Why? What are their dimensions?

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0
Ahahahha ahahahahhashdgzbbahaah
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The area of a square piece of land is 784metersquared .What is the perimeter​
Marta_Voda [28]

Answer:

112 m

Step-by-step explanation:

The area (A) of a square is

A = s² ( s is the length of side )

Here A = 784 , then

s² = 784 ( take the square root of both sides )

s = \sqrt{784} = 28

Then

perimeter = 4s = 4 × 28 = 112 m

7 0
3 years ago
Read 2 more answers
Use the fact that sin 38 ≈ 0.6157 to solve m.
Anni [7]
Use cos^-1(0.6157) and u might find the answer
6 0
2 years ago
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What is -5/8 + 3/4 I cannot seem to figure it out correctly thanks!
Pepsi [2]

Step-by-step explanation:

-5/8 + 3/4

= -5/8 + 6/8

=1/8

7 0
3 years ago
PLEASE HELP ASAP DUE IN 3 MINUTES
Inga [223]

Answer:

<u>1728 in²</u>

Step-by-step explanation:

For the area of B, you need to find the length and width (height and base, whatever you want to call it).

For the height, you would need to do: 144 - 36 - 24 - 36 = <u>48 inches</u>

For the base, you would need to do: 60 - 24 = <u>36 inches</u>

Now you multiply the base and height to get the area: 48 x 36 = <u>1728 in²</u>

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=
stepan [7]
\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\&#10;-----------------------------\\\\&#10;recall\quad \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)&#10;\\\\\\&#10;now\quad a^2+5a-6\implies (a+6)(a-1)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\&#10;-----------------------------\\\\&#10;

\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\&#10;-----------------------------\\\\&#10;thus&#10;\\\\\\&#10;\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}
6 0
3 years ago
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