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jekas [21]
3 years ago
14

The smaller of two numbers is one-half the larger, and their sum is 27. Find the numbers. I need an answer in 10 minutes

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

18 and 9

Step-by-step explanation:

The numbers are x and 1/2x.

x + 1/2x = 27

3/2x = 27

x = 18 so the numbers of 18 and 9.

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HELP PLEASE!!! <br>the question and answer are in the image attached​
RideAnS [48]

Answer:

g(x)=\sqrt[3]{x-3}+4

Step-by-step explanation:

The function g(x) is a shifted version of the function f(x); f(x) is shifted by 3 along x-axis and by 4 along y-axis.

Another way of thinking about this is that the function g(x) contains points (3, 4); therefore,

g(x)=\sqrt[3]{x-3}+4

which goes through the point (3, 4).

8 0
3 years ago
Find the product<br> (n3)2 • (n5)4<br><br> n _
ASHA 777 [7]

Answer:

8n^8

Step-by-step explanation:

n3*2*n5*4

=8*n8

8n^8

6 0
3 years ago
Read 2 more answers
Whats balance fe+30^2 &gt;fe^2O^3
blsea [12.9K]

Answer:

You are given:

4Fe+3O_2 -> 2Fe_2O_3

4:Fe:4

6:O_2:6

You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.

For added benefit consider the following equation:

CH_4+O_2-> CO_2+2H_2O

ASK: Is this equation balanced? Quick answer: No

ASK: So how do we know and how do we then balance it?

DO: Count the number of each atom type you have on each side of the equation:

1:C:1

4:H:4

2:O:4

As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:

CH_4+color(red)(2)O_2-> CO_2+2H_2O

1:C:1

4:H:4

4:O:4

Everything is now balanced.

Step-by-step explanation:

5 0
2 years ago
Pls help this is pretty urgent
KIM [24]

Answer:

(a)  0

(b)  f(x) = g(x)

(c)  See below.

Step-by-step explanation:

Given rational function:

f(x)=\dfrac{x^2+2x+1}{x^2-1}

<u>Part (a)</u>

Factor the <u>numerator</u> and <u>denominator</u> of the given rational function:

\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}

Substitute x = -1 to find the limit:

\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0

Therefore:

\displaystyle \lim_{x \to -1}f(x)=0

<u>Part (b)</u>

From part (a), we can see that the simplified function f(x) is the same as the given function g(x).  Therefore, f(x) = g(x).

<u>Part (c)</u>

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero).  Therefore, the quotient approaches infinity.

\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty

5 0
1 year ago
Read 2 more answers
Solve the following question algebraically, show your work<br><br> 13 + w/7 &lt;-(fraction) = -18
evablogger [386]

Solve for w: by simplifying both sides of the equation, then isolating the variable.

w=-217

Work: 1.  Subtract 13 from both sides (w/7 = -18 - 13), 2.Simplify -18-13 to -31 (w/​7=-31), 3.Multiply both sides by 7 (w = -31 * 7), 4. Simplify 31*7 to 217 (w=-217)

8 0
3 years ago
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