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Salsk061 [2.6K]
3 years ago
12

I want to discard my old computer and securely erase the data from my hard drive.

Computers and Technology
1 answer:
FrozenT [24]3 years ago
3 0
Wipe off the hard drive with a software eraser but it won't be quick and won't work on defective disks
You might be interested in
What year did apple computer introduce the first ipod?.
Lady bird [3.3K]
Apple first released the first ipod in 2001
8 0
2 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
2 years ago
What is the role of the ieee in computer networking and wireless communications?
steposvetlana [31]
<span>An organization that sets standards for computer networking and wireless communications.</span>
8 0
3 years ago
Contast between backups controlled within the SAN and backups controlled from the application server.
luda_lava [24]

Answer and Explanation:

Backup control within the SAN is one which confines the backup to the SAN and does not pass it via corporate network.

Backup traffic within the SAN are  easier to maintain and easily handled in contrast to the application server.

Backup in SAN is governed by  such applications and mechanism which allows the easy handling of the backup traffic which is not provided by the application servers.

In case of occurrence of any failure,  unlike application server, SAN provides smooth and fast migration

SAN holds data in cluster  by the use of backup techniques not used in application server.

6 0
3 years ago
Convert the following MIPS assembly code snippet into machine language (hex). Write the code in a memory arrangement (address -
Snezhnost [94]

Answer:

Check the exlanation

Explanation:

1) add $s0,$s0,$s1 \rightarrow R-format

   

opcode                 rs        rt      rd          shamt      function

000000            $s0       $s1    $s0        00000    100000

000000            10000  10001  10000    00000  100000

  = 0X42118020

2) lw $s0,0X20($t7)\rightarrow I-format

opcode                     rs      rt            offset

100000                  $s0     $t7          0X20

100000               10000    01111       0000000000010000

  = 0X820F0010

3) addi $s0,$s0,-10 \rightarrow I-format

opcode             rs           rt            offset

001000            $s0         $s0       -10

001000             10000   10000    1111111111110110

= 0X2210FFF6

4) ori $s1,$a0,100 \rightarrow I-format

opcode             rs        rt            offset

001101             $s0     $a0         100

001101            10000  00100    0000000001100100

= 0X36040064

5) j 0X400C \rightarrow J-format

opcode  rs

000010  0X400C

000010  0000000000100000000001100

= 0X0800400C

4 0
3 years ago
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