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3 years ago

What is f(5) for f(x) = 4x^2-5x+2

Mathematics

1 answer:

vovikov84 [41]3 years ago

7 0

im not sure if it correct or not but i'm trying to help you

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A 16.5 ft tall giraffe casts a 12 ft shadow. At the same time, a zookeeper casts a 4 ft shadow. How tall is the zookeeper?

Stels [109]

12 ft shadow / 4 ft shadow = 3

16.5 ft / 3 = 5.5 ft

The zookeeper is 5.5 feet tall

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A jar was full of quarters and $1 coins. 2/5 of the coins in the jar were quarters. The rest were $1 coins. There were 10 more $

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Answer:

50 coins

Step-by-step explanation:

if there is 1/5 more 1 dollar coins than quarters that means 1/5 of the total number is equal to 10, and if 1/5 is 10 that means 5*10=50 is the total number

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Two consecutive even whole numbers have a product of 360. What is the smaller of the<br> two number?

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Answer:

let one even number be N

and another even number be N(N+2)

N(N+2)=360

n^2+2n-360=0

n^2+20n-18n-360=0

value of N= -20 ,18

but -20 not accepted

smaller number 18

Step-by-step explanation:

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16% of ____ shirts are 44<br> How many shirts are there?

yawa3891 [41]

I don’t know, I forgot how to solve problems like this, look it up

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago