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Marina CMI [18]
3 years ago
8

(x+0)(x-3)(x+0)(x+5)

Mathematics
1 answer:
pshichka [43]3 years ago
3 0

Answer:

x^2 + 2x - 15

Step-by-step explanation:

(x-3)(x+5) = x^2 + 2x - 15

hope this helps, pls mark brainliest :D

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Solve the below system of equations using the best method. Please describe the method used [substitution, graphing, elimination,
Veseljchak [2.6K]
1). Since you have -2y and 4y, elimination is easy to do for solving for x..
Keep the first equation and multiply the second equation by 2. Then add.

5x - 2y = -1
8x + 4y = 56

10x - 4y = -2
8x + 4y = 56
-----------------
18x       = 54

x = 3

Now we can use substitution to solve for y.
Substitute 3 for x in the first original equation and solve for y.

5x - 2y = -1

5(3) - 2y = -1

15 - 2y = -1

-2y = -16

y = 8

(3, 8)


2.)

3x - y = =16
-4x - y = 21

Multiply both sides of the first equation by -1 to change all signs. Then when you add the equations, you eliminate y and solve for x.

-3x + y = 16
-4x - y = 21
-----------------
-7x       = 37

x = -37/7

Now multiply the first original equation by 4 and the second original by 3 to eliminate x and solve for y.

 12x - 4y = -64
-12x - 3y =  63
---------------------
         -7y   = -1

y = 1/7

Solution: (-37/7, 1/7)
4 0
3 years ago
What fraction is closest to .39. 1/3 or 2/5?
Maksim231197 [3]
2/5 would be closer

since 2/5 is 0.4 
and 1/3 is 0.333...

You can draw a number line to see how 2/5 ( 0.4) is closest to 0.39 
6 0
3 years ago
a colony of fruit flies doubles every 10 minutes, if there are 19683 fruit flies now how many were present an hour ago
Aliun [14]
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4 0
4 years ago
Read 2 more answers
A piece of wire is 76cm long. It is cut into two unequal parts and each part is bent into a square. The sum of the areas of the
NemiM [27]

Answer:

The length of the shorter part of the wire is 24 centimeters.

Step-by-step explanation:

Let L the total length of the piece of wire, where L-x and x are the perimeters of the greater and lesser squares. All lengths are measured in centimeters. Since squares have four sides of equal length, the side lengths for the greater and lesser squares are \frac{L-x}{4} and \frac{x}{4}. From statement we find that the sum of the areas of the two squares (A), measured in square centimeters, is represented by the following expression:

A = \left(\frac{L-x}{4} \right)^{2}+\left(\frac{x}{4} \right)^{2} (1)

And we expand this polynomial below:

A = \frac{L^{2}-2\cdot L\cdot x +x^{2}}{16} + \frac{x^{2}}{16}

A = \frac{L^{2}-2\cdot L\cdot x +2\cdot x^{2}}{16}

2\cdot x^{2}-2\cdot L\cdot x +L^{2}-16\cdot A = 0 (2)

If we know that L = 76\,cm and A = 205\,cm^{2 }, then the length of the shorter part of the wire is:

2\cdot x^{2}-152\cdot x +2496 = 0

By the Quadratic Formula, we determine the roots associated with the polynomial:

x_{1} = 52\,cm, x_{2} = 24\,cm

The length of the shorter part of the wire corresponds to the second root. Hence, the length of the shorter part of the wire is 24 centimeters.

3 0
3 years ago
HELP HELP ASAPP!!!! PLS
ira [324]

Answer:

D)  reflection followed by a dilation

Step-by-step explanation:

3 0
3 years ago
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