Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Answer:
I think that the answer isssss B
<u>Answer:</u>
- The solution to the equation is 4.
<u>Step-by-step explanation:</u>
<u>Work:</u>
- 6x - 3 = 21
- => 6x = 21 + 3
- => 6x = 24
- => x = 4
Hence, <u>the solution to the equation is 4.</u>
Hoped this helped.

Answer:
45231 = 
Step-by-step explanation:
Given the number:
45,231
We have To write the given number in the expanded form.
Solution:
First of all, let us write the different digits of the number:
Unit's digit = 1
Ten's digit = 3
Hundred's digit = 2
Thousand's digit = 5
Ten thousand's digit = 4
Unit's digit has to be multiplied with 1.
Ten's digit has to be multiplied with 10.
Hundred's digit has to be multiplied with 100.
Thousand's digit has to be multiplied with 1000.
Ten Thousand's digit has to be multiplied with 10000.
And then they have to be added so that the number gets formed.
45231 = 