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Sever21 [200]
3 years ago
9

1 5/7÷4/9 = what's the answer and how to write the problem out

Mathematics
1 answer:
balu736 [363]3 years ago
4 0

The solution to given expression 1\frac{5}{7} \div \frac{4}{9} is \frac{27}{7} or 3.8571

<em><u>Solution:</u></em>

Given expression is:

1\frac{5}{7} \div \frac{4}{9}

<em><u>First let us convert the mixed fraction to improper fraction</u></em>

Multiply the whole number by the denominator.

Add the answer from Step 1 to the numerator.

Write answer from Step 2 over the denominator.

Thus we get,

1\frac{5}{7} = \frac{1 \times 7 + 5}{7} = \frac{12}{7}

Now the given expression becomes,

1\frac{5}{7} \div \frac{4}{9} = \frac{12}{7} \div \frac{4}{9}

Convert the problem to multiplication by changing the division sign to multiplication and inverting the fraction to the right of the sign

\frac{12}{7} \div \frac{4}{9} = \frac{12}{7} \times \frac{9}{4}

Multiply the numerators, multiply the denominators, and leave the product in factored form

\frac{12}{7} \times \frac{9}{4} = \frac{27}{7}

In decimal form we get,

\frac{27}{7} = 3.8571

Thus the solution to given expression is \frac{27}{7} or 3.8571

You might be interested in
How many positive four-digit integers are multiples of 5 and less than 4,000
Volgvan

Answer:

  Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

Explanation:

 Lowest four digit positive integer = 1000

 Highest four digit positive integer less than 4000 = 3999

 We know that multiples of 5 end with 0 or 5 in their last digit.

 So, lowest four digit positive integer which is a multiple of 5 = 1000

 Highest four digit positive integer less than 4000 which is a multiple of 5  = 3995.

 So, the numbers goes like,

       1000, 1005, 1010 .....................................................3990, 3995

 These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.

          An = a + (n-1)d  

           3995 = 1000 + (n-1)x 5

           (n-1) x 5 = 2995

           (n-1) = 599

            n = 600

 So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600

6 0
3 years ago
Please help me its really important
Serga [27]

Answer:

I think that the answer isssss B

5 0
3 years ago
Solve the equation, show all your work:<br><br> 6x - 3 = 21
OlgaM077 [116]

<u>Answer:</u>

  • The solution to the equation is 4.

<u>Step-by-step explanation:</u>

<u>Work:</u>

  • 6x - 3 = 21
  • => 6x = 21 + 3
  • => 6x = 24
  • => x = 4

Hence, <u>the solution to the equation is 4.</u>

Hoped this helped.

BrainiacUser1357

5 0
3 years ago
What is 45,231 written in expanded form? 2 x 10,000 + 1 x 1,000 + 3 x 100 + 5 x 10 + 4 2 x 10,000 + 3 x 1,000 + 1 x 100 + 4 x 10
adoni [48]

Answer:

45231 = 4 \times 10000 + 5\times 1000 +2 \times 100 + 3\times 10 +1 \times 1

Step-by-step explanation:

Given the number:

45,231

We have To write the given number in the expanded form.

Solution:

First of all, let us write the different digits of the number:

Unit's digit = 1

Ten's digit = 3

Hundred's digit = 2

Thousand's digit = 5

Ten thousand's digit = 4

Unit's digit has to be multiplied with 1.

Ten's digit has to be multiplied with 10.

Hundred's digit has to be multiplied with 100.

Thousand's digit has to be multiplied with 1000.

Ten Thousand's digit has to be multiplied with 10000.

And then they have to be added so that the number gets formed.

45231 = 4 \times 10000 + 5\times 1000 +2 \times 100 + 3\times 10 +1 \times 1

3 0
3 years ago
Help please, my teacher is horrible at explaning
Inessa05 [86]

10 hours and 10 minutes

6 0
4 years ago
Read 2 more answers
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