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sergij07 [2.7K]
3 years ago
11

Can any one tell me if this is right

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
The vertex should be at (1,2) because the equation is in vertex form.
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Simplify 7 + (−3).<br><br> a. −10<br><br> b. −4<br><br> c. 4<br><br> d. 10
Vikentia [17]
C. Your Answer Is 4. Which Is C


3 0
4 years ago
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. Show ALL work for the following problem... if you write the answer only, you will not get brainlist: 2(x - 2) = 4x - 6(x - 2)
Rom4ik [11]

Distribute 2 to x and -2, and -6 to x and -2

2(x - 2) = 2x - 4

-6(x - 2) = -6x + 12

2x - 4 = 4x - 6x + 12

Simplify. Combine like terms

2x - 4  = (4x - 6x) + 12

2x - 4 = -2x + 12

Isolate the x. Add 4 to both sides, and 2x to both sides

2x (+2x) - 4 (+4) = -2x (+2x) + 12 (+4)

2x + 2x = 12 + 4

Simplify

4x = 16

Isolate the x. Divide 4 from both sides

4x/4 = 16/4

x = 16/4

x = 4

4 is your answer for x.

hope this helps

6 0
3 years ago
What is the quadratics formula?
8_murik_8 [283]
This is the quadratic formula

8 0
3 years ago
Read 2 more answers
How do you solve thsi
VLD [36.1K]
You multiply the length of the model car by the meters from the actual car. It’s easier to convert one unit of measurement to match with the other. I found it easier to convert 18.2 cm to meters which is 0.182 m. Now we multiply 0.182m by 0.3m to get the length of the actual car.

The answer would be 0.0546m. Or if you prefer centimeters, then the answer would be 5.46 cm. Either way is fine.

Hope this helped, please let me know if I was correct. :D
5 0
3 years ago
Which expression is equivalent to...
torisob [31]

Answer:

x^{\frac{2}{7} } y^{-\frac{3}{5} } \\  i.e answer A.

Step-by-step explanation:

This question involves knowing the following power/exponent rule:

\sqrt[n]{x^m} = x^\frac{m}{n} \\\\so \sqrt[7]{x^2} = x^\frac{2}{7} \\\\and  \\\\ \sqrt[5]{y^3} = y^\frac{3}{5} \\

Next, when a power is on the bottom of a fraction, if we want to move it to the top, this makes the power become negative.

so the y-term, when moved to the top of the fraction, becomes:

y^{-\frac{3}{5} } \\

So the answer is: x^{\frac{2}{7} } y^{-\frac{3}{5} } \\

7 0
3 years ago
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