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4 years ago

How do you solve this? 3x(x+4)=0

Mathematics

2 answers:

Lelechka [254]4 years ago

3 0

Answer:

3x=0 or x+4=0

x=0 or x=−4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x2+12x=0

Step 2: Factor left side of equation.

3x(x+4)=0

Step 3: Set factors equal to 0.

3x=0 or x+4=0

x=0 or x=−4

miss Akunina [59]4 years ago

3 0

Answer:

3x^2+12x

Step-by-step explanation:

I can't quite remember but I believe that is the answer

You distribute the 3x into the parenthesis

3x(x)+3x(4)

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7(2m-1)-35m=65(4-3m)

ycow [4]

Answer:

m = 267/174

Step-by-step explanation:

7(2m-1)-35m=65(4-3m)
14m - 7 - 35m = 260 - 195m
-21m + 195m = 260 + 7
174m = 267
m = 267/174

3 0

3 years ago

Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8

goblinko [34]

$\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y = \frac{17}{14} } \atop {x+7y=8}} \right.$

To solve this system by substitution, first isolate x in the second equation.

$x+7y=8$
$x+7y-7y=8-7y$
$x=8-7y$

Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
$3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}$
$72-63y+8y=17$
$72-55y=17$
$-55y=17-72$
$-55y=-55$
$y=1$

Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
$x=1$

Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
$x=1 \\ y=1$

5 0

3 years ago

PLEASE HELP.Ill mark you brainliest if its right

Lena [83]

Answer:

Step-by-step explanation:

1.) y= 1/5x - 2

2.) y = 1x + 2

3.) y = 2x + 4

4.) y = 1x + 4

5.) y = 1/3x - 4

6.) y = 1/2x - 3