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Marysya12 [62]
3 years ago
9

What the slope of (5,5) and (0,1) ​

Mathematics
2 answers:
storchak [24]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:

Slope = 4/5

Discussion:

Slope = (change in y) / (change in x)

Slope =

(1-5)/(0-5)  =

-4/-5 =

4/5

Thank you,

MrB

777dan777 [17]3 years ago
3 0

Answer:

4/5

Step-by-step explanation:

Use formula y2-y1/x2-x1

X1. Y1. X2. Y2

(5, 5) (0, 1)

Then

1-5/0-5

And once you simply you get the answer

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There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
Select the property of equality used to arrive aSelect the property of equality used to arrive at the conclusion.
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would it be b

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Find the sum of 10 minus the sum of 2 and 3
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Step-by-step explanation:

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The longest side of triangle is 10 cm which group of line segments could form the other 2 sides of the triangle
dmitriy555 [2]

Answer:

The group of line segments that could form the other 2 sides of the triangle is;

B. 7 cm and 8 cm

Step-by-step explanation:

The triangle inequality theorem states that the sum of the length of any two sides of a triangle is larger than the length of the third side

The given parameter of the triangle is that the length of the longest side of the triangle = 10 cm

Let, 'a', and 'b', represent the remaining two sides of the triangle

Therefore, by the triangle inequality theorem, we have;

(1) a + b > 10 cm

(2) 10 cm + a > b

(3) 10 cm + b > a

The option that satisfies condition (1), (2), and (3) are options 'B' and 'D', for which we have;

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10 cm + 8 cm = 18 cm > 7 cm

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10 cm + 9 cm = 19 cm > 10 cm

10 cm + 10 cm = 20 cm > 9 cm

Therefore, the possible combination of the other two sides are;

7 cm and 8 cm or 9 cm and 10 cm

However, a side of option 'D' is 10 cm and given that the longest side of the triangle = 10 cm, the length of each of the other two side should be less than 10 cm and the only given possible combination of the other two side should be option 'B', 7 cm and 8 cm.

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6 potted plants can be arranged 720 different ways.
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