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qwelly [4]
3 years ago
11

A triangle has the following side lengths: x - 2, x, and 3x + 1. Another triangle has the following side lengths: 2x - 5, x + 4,

6x - 7. If the perimeters of the two triangles are equal, what is x?
Mathematics
1 answer:
notka56 [123]3 years ago
5 0

we know that

Perimeter of a triangle is equal to

P=a+b+c

where

a,b and c are the length sides of the triangle

<u>Find the perimeter of the triangles</u>

<u>Triangle N 1</u>

P=(x-2)+(x)+(3x+1)-------> P=5x-1

<u>Triangle N 2</u>

P=(2x-5)+(x+4)+(6x-7)------> P=9x-8

equate the perimeters

5x-1=9x-8--------> 9x-5x=-1+8-------> 4x=7

x=7/4------> x=1.75

therefore

the answer is

x=1.75

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