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3 years ago

Help need to divide the fraction

Mathematics

1 answer:

antoniya [11.8K]3 years ago

4 0

Hello There!

So we divide fractions by multiplying by the reciprocal.

So let’s change 6/7 divided by 3/8 to 6/7 multiplied by 8/3.

Once we do that, we can start our multiplication.

Once we multiply, we get 48/21

We can both divide these by 3 to simplify it so once we divide we will get

16/7

This can be turned in a mix number and it would be 2 and 2/7

You might be interested in

Can someone do 15?!?!?

andrew-mc [135]

<u>Given</u>:

The given triangle is a right triangle.

The length of the hypotenuse is 31 units.

The length of the leg is 23 units.

One of the angle is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

$sin \ \theta=\frac{opp}{hyp}$

Substituting $\theta=x$ , the side opposite to the angle x measures 23 units and the hypotenuse is 31.

Thus, we have;

$sin \ x=\frac{23}{31}$

Dividing, we get;

$sin \ x=0.74$

Taking $sin ^{-1}$ on both sides of the equation, we get;

$x=sin^{-1}(0.74)$

$x=47.7$

Rounding off to the nearest whole integer, we get;

$x=48$

Thus, the value of x is 48°

Hence, Option c is the correct answer.

5 0

3 years ago

Is (6,-10) a solution of y=3x-8

Vitek1552 [10]

You can easily test this if you know that (6, -10) corresponds to (X, Y). Knowing this, you can:

X = 6
Y = -10

you put this into your equation:

-10 = 3*6 - 8

calculate it:

-10 = 18 - 8
-10 = 10
This is not true of course, -10 is not equal to 10. Therefore, (6, -10) is not a solution of y = 3x-8 :)

6 0

3 years ago

When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con

marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force $F$ applied to an object with mass $m$ is directly proportional to its acceleration $a$ :

$F=ma$ (1)

If we isolate $a$ :

$a=\frac{F}{m}$ (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

$m_{1}=4 kg$

$a_{1}=5 m/s^{2}$

$F=m_{1}a_{1}$ (3)

$F=(4 kg)(5 m/s^{2)$ (4)

$F=20 N$ (5)

If we apply this same force calulated in (4) in another object with an acceleration of $a_{2}=2 m/s^{2}$ , its mass $m_{2}$ will be:

$F=m_{2}a_{2}$ (6)

$20 N=m_{2}2 m/s^{2}$ (7)

Finding $m_{2}$ :

$m_{2}=10 kg$ This is the mass of the object

4 0

3 years ago

Solve kx + 7 = 4 for x.

Leya [2.2K]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Amari claims that a rectangle is sometimes a parallelogram but a parallelogram is always a

Maslowich

Answer:

The statement is false.

Step-by-step explanation:

A parallelogram is a figure of four sides, such that opposite sides are parallel

A rectangle is a four-sided figure such that all internal angles are 90°

Here, the statement is:

"A rectangle is sometimes a parallelogram but a parallelogram is always a

rectangle."

Here if we found a parallelogram that is not a rectangle, then that is enough to prove that the statement is false.

The counterexample is a rhombus, which is a parallelogram that has two internal angles smaller than 90° and two internal angles larger than 90°, then this parallelogram is not a rectangle, then the statement is false.

The correct statement would be:

"A parallelogram is sometimes a rectangle, but a rectangle is always a parallelogram"

6 0

2 years ago

Help need to divide the fraction ​

Help need to divide the fraction