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3 years ago

What is 2+(9-5)x7-3/4

Mathematics

1 answer:

Cloud [144]3 years ago

5 0

I got 9.75 hope it's right

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Solve for x. 4−(2x+4)=5

WITCHER [35]

$4-(2x+4)=5\\-2x-4=1\\-2x=5\\x=-2.5$

Put it back into the equation,

$4-(2x+4)=5\\4-(2(-2.5)+4)=5\\4-(-5+4)=5\\4-(-1)=5\\5=5$

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3 0

3 years ago

If we play a game where I start with 2 dollars and you start with one dollar, and I have a probability of 1/3 of winning a dolla

Vadim26 [7]

Answer:

1/3 or 0.33

Step-by-step explanation:

Hope it helps

LMK if it does and weather it is wrong or right

8 0

3 years ago

Find the slope of the line passing through the points (-6, -3) and (4, -3).

miskamm [114]

Answer:

m = 0

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Simply plug in the coordinates into the formula:

m = (-3 + 3)/(4 - 6)

m = 0/-2

m = 0

6 0

3 years ago

HELP PLEASE DEADLINE

ELEN [110]

Reason 1: Given.

Reason 2: Vertical angles

Reason 3: Angle, Side, Angle(ASA)

8 0

3 years ago

A ball is thrown at an initial height of 7 feet with an initial upward velocity at 27 ft/s. The balls height h (in feet) after t

lianna [129]

Answer:

The height of ball is 17 ft at t=0.55 and t=1.14.

Step-by-step explanation:

The general projectile motion is defined as

$y=-16t^2+vt+y_0$

Where, v is initial velocity and y₀ is initial height.

It is given that the initial height is 7 and the initial upward velocity is 27.

Substitute v=27 and y₀=7 in the above equation to find the model for height of the ball.

$h(t)=-16t^2+27t+7$

The height of ball is 17 ft. Put h(t)=17.

$17=-16t^2+27t+7$

$0=-16t^2+27t-10$

On solving this equation using graphing calculator we get

$t=0.549,1.139$

$t\approx 0.55,1.14$

Therefore the height of ball is 17 ft at t=0.55 and t=1.14.

3 0

3 years ago